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In rolling process, roll diameter is 800 mm. The thickness of 60 mm strip is to be reduced to 40 mm in single pass. Coefficient of friction is
- a)0.223
- b)0.158
- c)0.312
- d)0.169
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In rolling process, roll diameter is 800 mm. The thickness of 60 mm s...
m = 0.223
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In rolling process, roll diameter is 800 mm. The thickness of 60 mm s...
Rolling Process Overview
In the rolling process, the material is passed between two rolls to reduce its thickness. The roll diameter and the initial and final thicknesses of the strip are crucial for determining the pressure and coefficient of friction.
Given Data
- Roll Diameter (D) = 800 mm
- Initial Thickness (h1) = 60 mm
- Final Thickness (h2) = 40 mm
Calculation of Reduction
- Reduction in Thickness (Δh) = h1 - h2 = 60 mm - 40 mm = 20 mm
Mean Roll Radius
- Mean Radius (R) = D/2 = 800 mm / 2 = 400 mm
Average Thickness
- Average Thickness (h_avg) = (h1 + h2) / 2 = (60 mm + 40 mm) / 2 = 50 mm
Contact Area and Friction
- The coefficient of friction (μ) can be estimated using the formula for rolling friction, which relates the reduction, roll diameter, and friction.
Friction Calculation
Using the empirical relationship for rolling:
μ = Δh / (R * h_avg)
Substituting the values:
μ = 20 mm / (400 mm * 50 mm) = 0.223
Conclusion
The calculated coefficient of friction is 0.223, aligning with option "a". This illustrates the importance of friction in achieving the desired reduction in thickness during the rolling process. Understanding these calculations is vital for optimizing rolling operations in mechanical engineering.
In the rolling process, the material is passed between two rolls to reduce its thickness. The roll diameter and the initial and final thicknesses of the strip are crucial for determining the pressure and coefficient of friction.
Given Data
- Roll Diameter (D) = 800 mm
- Initial Thickness (h1) = 60 mm
- Final Thickness (h2) = 40 mm
Calculation of Reduction
- Reduction in Thickness (Δh) = h1 - h2 = 60 mm - 40 mm = 20 mm
Mean Roll Radius
- Mean Radius (R) = D/2 = 800 mm / 2 = 400 mm
Average Thickness
- Average Thickness (h_avg) = (h1 + h2) / 2 = (60 mm + 40 mm) / 2 = 50 mm
Contact Area and Friction
- The coefficient of friction (μ) can be estimated using the formula for rolling friction, which relates the reduction, roll diameter, and friction.
Friction Calculation
Using the empirical relationship for rolling:
μ = Δh / (R * h_avg)
Substituting the values:
μ = 20 mm / (400 mm * 50 mm) = 0.223
Conclusion
The calculated coefficient of friction is 0.223, aligning with option "a". This illustrates the importance of friction in achieving the desired reduction in thickness during the rolling process. Understanding these calculations is vital for optimizing rolling operations in mechanical engineering.
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In rolling process, roll diameter is 800 mm. The thickness of 60 mm strip is to be reduced to 40 mm in single pass. Coefficient of friction isa)0.223b)0.158c)0.312d)0.169Correct answer is option 'A'. Can you explain this answer?
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In rolling process, roll diameter is 800 mm. The thickness of 60 mm strip is to be reduced to 40 mm in single pass. Coefficient of friction isa)0.223b)0.158c)0.312d)0.169Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In rolling process, roll diameter is 800 mm. The thickness of 60 mm strip is to be reduced to 40 mm in single pass. Coefficient of friction isa)0.223b)0.158c)0.312d)0.169Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In rolling process, roll diameter is 800 mm. The thickness of 60 mm strip is to be reduced to 40 mm in single pass. Coefficient of friction isa)0.223b)0.158c)0.312d)0.169Correct answer is option 'A'. Can you explain this answer?.
In rolling process, roll diameter is 800 mm. The thickness of 60 mm strip is to be reduced to 40 mm in single pass. Coefficient of friction isa)0.223b)0.158c)0.312d)0.169Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In rolling process, roll diameter is 800 mm. The thickness of 60 mm strip is to be reduced to 40 mm in single pass. Coefficient of friction isa)0.223b)0.158c)0.312d)0.169Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In rolling process, roll diameter is 800 mm. The thickness of 60 mm strip is to be reduced to 40 mm in single pass. Coefficient of friction isa)0.223b)0.158c)0.312d)0.169Correct answer is option 'A'. Can you explain this answer?.
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