Three blocks A B and C are kept as shown in the figure the coefficient...
Analysis:
Frictional forces will act between blocks A and B, B and C, and between block C and the ground. The total work done by friction can be calculated by finding the work done by each individual frictional force.
Work done by friction between A and B:
- Frictional force, \( F_{AB} = \mu_{AB} \times N_{AB} \), where \( \mu_{AB} = 0.2 \) and \( N_{AB} = m_A \times g = 3 \times 9.8 = 29.4 \, N \)
- Work done by friction between A and B, \( W_{AB} = F_{AB} \times d_{AB} = 29.4 \times 0.2 \times d_{AB} \)
Work done by friction between B and C:
- Frictional force, \( F_{BC} = \mu_{BC} \times N_{BC} \), where \( \mu_{BC} = 0.1 \) and \( N_{BC} = m_B \times g = 2 \times 9.8 = 19.6 \, N \)
- Work done by friction between B and C, \( W_{BC} = F_{BC} \times d_{BC} = 19.6 \times 0.1 \times d_{BC} \)
Work done by friction between C and ground:
- Frictional force, \( F_{CG} = \mu_{CG} \times N_{CG} = 0 \) as \( \mu_{CG} = 0 \)
- Work done by friction between C and ground, \( W_{CG} = 0 \)
Total work done by friction:
- Total work done by friction, \( W_{total} = W_{AB} + W_{BC} + W_{CG} \)
Therefore, the total work done by friction in this scenario can be calculated by adding the work done by friction between blocks A and B, B and C, and between block C and the ground.
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