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A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :
  • a)
    692 pJ
  • b)
    6 0 pJ
  • c)
    508 pJ
  • d)
    560 pJ
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A parallel plate capacitor having capacitance 12 pF is charged by a ba...
Charge remains same
so w.d.is equal to change in energy
(Q^2/2c)-(Q^2/2kc)
Q=cv
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A parallel plate capacitor having capacitance 12 pF is charged by a ba...

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A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :a)692 pJb)6 0 pJc)508 pJd)560 pJCorrect answer is option 'C'. Can you explain this answer?
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A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :a)692 pJb)6 0 pJc)508 pJd)560 pJCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :a)692 pJb)6 0 pJc)508 pJd)560 pJCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :a)692 pJb)6 0 pJc)508 pJd)560 pJCorrect answer is option 'C'. Can you explain this answer?.
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