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Two parallel plate of capacitance C and 2C are connected in parallel and charged to potential difference V.the battery is then disconnected and region between the plate of the capacitor C is completely filled with a material of dielectric constant K .the potential difference across the capacitor now becomes a)3v/k+2 b)kV. c)v/k. d)3/kv?
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Two parallel plate of capacitance C and 2C are connected in parallel a...
The original capacitance of the parallel combination of C and 2 C is = C +2C = 3C
Total charge Q = 3CV
When the capacitor C is filled with a dielectric, its capacitance becomes KC. 
Therefore, after the capacitor is filled with dielectric the capacitance of the combination, C' = KC + 2C = C (K + 2).
However, the charge remains the same, i.e. Q = 3CV
Therefore, the potential difference across the capacitors will be 
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Two parallel plate of capacitance C and 2C are connected in parallel a...
Explanation:
1. Initial Situation:
- Two capacitors of capacitance C and 2C are connected in parallel and charged to potential difference V.
- The total capacitance in parallel is C_eq = C + 2C = 3C.
- The total charge on the capacitors is Q = C_eq * V = 3CV.
2. After Inserting Dielectric:
- When a dielectric material of dielectric constant K is inserted between the plates of the capacitor C, the capacitance of C changes to KC.
- The total capacitance now becomes C_eq' = KC + 2C = KC + 2C.
- The total charge remains the same as before, Q = C_eq' * V = (KC + 2C)V.
3. Change in Potential Difference:
- The potential difference across the capacitors changes to V' due to the insertion of the dielectric material.
- Using the formula for capacitance, Q = C_eq' * V', we can find the new potential difference V'.
4. Final Potential Difference:
- Substituting the values, we get Q = (KC + 2C)V' = 3CV.
- Solving for V', we find V' = 3V/K + 2.
5. Conclusion:
- The potential difference across the capacitor after inserting the dielectric material becomes 3V/K + 2, which is option (a).
Community Answer
Two parallel plate of capacitance C and 2C are connected in parallel a...
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Two parallel plate of capacitance C and 2C are connected in parallel and charged to potential difference V.the battery is then disconnected and region between the plate of the capacitor C is completely filled with a material of dielectric constant K .the potential difference across the capacitor now becomes a)3v/k+2 b)kV. c)v/k. d)3/kv?
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Two parallel plate of capacitance C and 2C are connected in parallel and charged to potential difference V.the battery is then disconnected and region between the plate of the capacitor C is completely filled with a material of dielectric constant K .the potential difference across the capacitor now becomes a)3v/k+2 b)kV. c)v/k. d)3/kv? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two parallel plate of capacitance C and 2C are connected in parallel and charged to potential difference V.the battery is then disconnected and region between the plate of the capacitor C is completely filled with a material of dielectric constant K .the potential difference across the capacitor now becomes a)3v/k+2 b)kV. c)v/k. d)3/kv? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two parallel plate of capacitance C and 2C are connected in parallel and charged to potential difference V.the battery is then disconnected and region between the plate of the capacitor C is completely filled with a material of dielectric constant K .the potential difference across the capacitor now becomes a)3v/k+2 b)kV. c)v/k. d)3/kv?.
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