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A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11V is connected across it is :
  • a)
    11 × 10–5 W
  • b)
    11 × 10–4 W
  • c)
    11 × 105 W
  • d)
    11 × 10–3 W
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A current of 2 mA was passed through an unknown resistor which dissipa...
P = I2R
4.4 = 4 × 10–6 R
R = 1.1 × 106 Ω
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Most Upvoted Answer
A current of 2 mA was passed through an unknown resistor which dissipa...
The power dissipated by a resistor can be calculated using the formula:

P = I^2 * R

where P is the power, I is the current, and R is the resistance.

Given that the current is 2 mA (or 0.002 A) and the power is 4.4 W, we can rearrange the formula to solve for the resistance:

4.4 = (0.002)^2 * R

R = 4.4 / (0.002)^2
R = 4.4 / 0.000004
R = 1,100,000 ohms

Now, when an ideal power supply of 11V is connected across the resistor, the current can be calculated using Ohm's law:

I = V / R

I = 11 / 1,100,000
I = 0.00001 A (or 10 mA)

Finally, we can calculate the power dissipated by the resistor with the new current:

P = I^2 * R

P = (0.00001)^2 * 1,100,000
P = 0.0001 * 1,100,000
P = 110 W

Therefore, the dissipated power when an ideal power supply of 11V is connected across the resistor is 110 W.
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A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11V is connected across it is :a)11 × 10–5 Wb)11 × 10–4 Wc)11 × 105 Wd)11 × 10–3 WCorrect answer is option 'A'. Can you explain this answer?
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A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11V is connected across it is :a)11 × 10–5 Wb)11 × 10–4 Wc)11 × 105 Wd)11 × 10–3 WCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11V is connected across it is :a)11 × 10–5 Wb)11 × 10–4 Wc)11 × 105 Wd)11 × 10–3 WCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11V is connected across it is :a)11 × 10–5 Wb)11 × 10–4 Wc)11 × 105 Wd)11 × 10–3 WCorrect answer is option 'A'. Can you explain this answer?.
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