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The energy dissipated by a resistor is 10 mJ in 1 s when an electric current of 2 mA flows through it. The resistance is __________ Ω.
(Round off to the nearest integer)
(Round off to the nearest integer)
Correct answer is '2500'. Can you explain this answer?
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The energy dissipated by a resistor is 10 mJ in 1 s when an electric c...
To find the resistance, we can use the formula for power, which is the rate at which energy is dissipated:
Power = Energy / Time
In this case, the power dissipated is 10 mJ (or 0.01 J) and the time is 1 s. Therefore,
Power = 0.01 J / 1 s = 0.01 W
The formula for power is also given by:
Power = Current^2 * Resistance
We know the current is 2 mA (or 0.002 A). Substituting these values into the equation, we get:
0.01 W = (0.002 A)^2 * Resistance
Simplifying, we have:
0.01 W = 0.000004 A^2 * Resistance
Dividing both sides by 0.000004 A^2, we get:
Resistance = 0.01 W / 0.000004 A^2 = 2500 ohms
Therefore, the resistance is 2500 ohms.
Power = Energy / Time
In this case, the power dissipated is 10 mJ (or 0.01 J) and the time is 1 s. Therefore,
Power = 0.01 J / 1 s = 0.01 W
The formula for power is also given by:
Power = Current^2 * Resistance
We know the current is 2 mA (or 0.002 A). Substituting these values into the equation, we get:
0.01 W = (0.002 A)^2 * Resistance
Simplifying, we have:
0.01 W = 0.000004 A^2 * Resistance
Dividing both sides by 0.000004 A^2, we get:
Resistance = 0.01 W / 0.000004 A^2 = 2500 ohms
Therefore, the resistance is 2500 ohms.
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The energy dissipated by a resistor is 10 mJ in 1 s when an electric c...
Q = i2 RT
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The energy dissipated by a resistor is 10 mJ in 1 s when an electric current of 2 mA flows through it. The resistance is __________ Ω.(Round off to the nearest integer)Correct answer is '2500'. Can you explain this answer?
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