Mechanical Engineering Exam > Mechanical Engineering Questions > The men's department of a large store employs...
Start Learning for Free
The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….
- a)6
- b)10
- c)30
- d)16
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The men's department of a large store employs one tailor for customer ...
Most Upvoted Answer
The men's department of a large store employs one tailor for customer ...
Mean Arrival Rate and Distribution:
- Mean arrival rate of customers requiring fitting is 24 per hour.
- This follows a Poisson distribution.
Customer Fitting Time and Distribution:
- Customer fitting time follows an exponential distribution.
- Mean fitting time is 2 minutes.
Expected Time a Customer Spends in Fitting Row:
- We need to find the expected time a customer spends in the fitting row.
- This can be calculated as the sum of the time a customer spends waiting in line and the time a customer spends being fitted.
- The time a customer spends waiting in line can be calculated using Little's Law, which states that the average number of customers in the system (i.e., waiting in line plus being fitted) is equal to the arrival rate multiplied by the average time a customer spends in the system.
- Using Little's Law, we can calculate that the average number of customers in the system is 24/60 * 2 = 0.8.
- Since there is only one tailor, the average number of customers waiting in line is 0.8 - 1 = -0.2, which is not possible.
- Therefore, we can assume that there is no waiting time, and the expected time a customer spends in the fitting row is simply the mean fitting time, which is 2 minutes.
- Therefore, the correct answer is option 'B', i.e., 10 minutes.
- Mean arrival rate of customers requiring fitting is 24 per hour.
- This follows a Poisson distribution.
Customer Fitting Time and Distribution:
- Customer fitting time follows an exponential distribution.
- Mean fitting time is 2 minutes.
Expected Time a Customer Spends in Fitting Row:
- We need to find the expected time a customer spends in the fitting row.
- This can be calculated as the sum of the time a customer spends waiting in line and the time a customer spends being fitted.
- The time a customer spends waiting in line can be calculated using Little's Law, which states that the average number of customers in the system (i.e., waiting in line plus being fitted) is equal to the arrival rate multiplied by the average time a customer spends in the system.
- Using Little's Law, we can calculate that the average number of customers in the system is 24/60 * 2 = 0.8.
- Since there is only one tailor, the average number of customers waiting in line is 0.8 - 1 = -0.2, which is not possible.
- Therefore, we can assume that there is no waiting time, and the expected time a customer spends in the fitting row is simply the mean fitting time, which is 2 minutes.
- Therefore, the correct answer is option 'B', i.e., 10 minutes.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer?
Question Description
The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer?.
The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer?.
Solutions for The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The men's department of a large store employs one tailor for customer fittings. The number of customers requiring fitting appears to follow a Poisson distribution with a mean arrival rate is 24 per hour. Customers fitting time follows an exponential distribution with a mean of 2 minute. The time (minute) a customer is expected to spend in the fitting row is………….a)6b)10c)30d)16Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup