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For a linear transformation T : R10 → R6, the kernal has dimension 5. Then, the dimension of the range of T is
  • a)
    5
  • b)
    6
  • c)
    4
  • d)
    2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
For a linear transformation T : R10 → R6, the kernal has dimensio...
We are given a linear transformation T : R10 → R6 and ker T has dimension 5. We need to find the dimension of range T.
using rank nullity theorem, we get dim range T = dim R10 - dim ker T.
= 10 - 5 = 5
Therefore, the dim of range T is 5.
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Most Upvoted Answer
For a linear transformation T : R10 → R6, the kernal has dimensio...
To fully define the linear transformation T : R10, we need to specify its action on each element of R10. In other words, for every vector x = (x1, x2, ..., x10) in R10, we need to determine the corresponding image vector T(x) under the transformation T.

One possible way to define T is by specifying its action on the standard basis vectors of R10. The standard basis vectors of R10 are given by:

e1 = (1, 0, 0, 0, 0, 0, 0, 0, 0, 0)
e2 = (0, 1, 0, 0, 0, 0, 0, 0, 0, 0)
e3 = (0, 0, 1, 0, 0, 0, 0, 0, 0, 0)
...
e10 = (0, 0, 0, 0, 0, 0, 0, 0, 0, 1)

To define T, we can specify its action on each of these basis vectors. For example, we can define T(e1) = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10), T(e2) = (2, 3, 4, 5, 6, 7, 8, 9, 10, 1), T(e3) = (3, 4, 5, 6, 7, 8, 9, 10, 1, 2), and so on.

Once we have specified the action of T on the basis vectors, we can extend it to all vectors in R10 by linearity. That is, for any vector x = (x1, x2, ..., x10) in R10, we can calculate T(x) by taking a linear combination of the images of the basis vectors. For example, if we have defined T(e1) = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10), T(e2) = (2, 3, 4, 5, 6, 7, 8, 9, 10, 1), and T(e3) = (3, 4, 5, 6, 7, 8, 9, 10, 1, 2), then for any vector x = (x1, x2, ..., x10) in R10, we can calculate T(x) as:

T(x) = x1 * T(e1) + x2 * T(e2) + x3 * T(e3) + ... + x10 * T(e10)

In summary, to fully define the linear transformation T : R10, we need to specify its action on the standard basis vectors of R10, and then extend it to all vectors in R10 by linearity.
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For a linear transformation T : R10 → R6, the kernal has dimension 5. Then, the dimension of the range of T isa)5b)6c)4d)2Correct answer is option 'A'. Can you explain this answer? for Mathematics 2025 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about For a linear transformation T : R10 → R6, the kernal has dimension 5. Then, the dimension of the range of T isa)5b)6c)4d)2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mathematics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a linear transformation T : R10 → R6, the kernal has dimension 5. Then, the dimension of the range of T isa)5b)6c)4d)2Correct answer is option 'A'. Can you explain this answer?.
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