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Let ω be a complex number such that ω3 = 1 but ω ≠ 1.

If A = , then which of the following statementare true?

  • a)
    A is invertible

  • b)
    rank (A) = 1

  • c)
    1 is an eigen value of A

  • d)
    rank(A ) = 2

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let ω be a complex number such that ω3 = 1 but ω &ne...
Determinant of Matrix A = 0 so it is not invertible.

Since determinant of matrix is zero it eigen value is zero.

After converting the matrix into row echlon form we find that there exist only 1 non zero row hence the rank of the matrix is 1.
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Most Upvoted Answer
Let ω be a complex number such that ω3 = 1 but ω &ne...
We are given that the matrix

where ω be a complex number such that ω3 = 1, but ω ≠ 1

Applying the operations C3 --> C1 + C+ C3 this operation yields.
∴ Rank of A = 2      ( ∵ 1+ ω + ω2 = 0)
 
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Let ω be a complex number such that ω3 = 1 but ω ≠ 1.If A =,then which of the following statementare true?a)A is invertibleb)rank (A) = 1c)1 is an eigen value of Ad)rank(A ) = 2Correct answer is option 'B'. Can you explain this answer?
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