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A wood specimen containing 14C taken from an ancient palace showed 24 counts in 3 minutes per gram of carbon in a detector. However, a fresh wood showed 52 counts in 2 minutes per gram of carbon. Assuming no background signal in the detector and half life of 14C as 5730 years, the age (in years) of the wood specimen is _______
    Correct answer is between '9600,9900'. Can you explain this answer?
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    A wood specimen containing 14C taken from an ancient palace showed 24 ...
    **Question:**
    A wood specimen containing 14C taken from an ancient palace showed 24 counts in 3 minutes per gram of carbon in a detector. However, a fresh wood showed 52 counts in 2 minutes per gram of carbon. Assuming no background signal in the detector and half life of 14C as 5730 years, the age (in years) of the wood specimen is _______Correct answer is between '9600,9900'. Can you explain this answer?

    **Solution:**

    The age of the wood specimen can be determined using the concept of radioactive decay.

    **Radioactive Decay:**
    Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting ionizing particles or radiation. This process is random and cannot be predicted with certainty. The decay rate is measured by the number of radioactive decays per unit time.

    **Half-life:**
    The half-life of a radioactive element is the time it takes for half of the atoms in a sample to decay. For 14C, the half-life is 5730 years.

    **Carbon Dating:**
    Carbon dating is a method used to determine the age of an object containing organic material by measuring the amount of 14C in the sample. When an organism dies, it stops taking in carbon, and the 14C in its body begins to decay. By comparing the amount of 14C in a sample to the amount of 14C in a fresh sample, we can determine the age of the sample.

    **Calculation:**

    Let the age of the wood specimen be x years.

    The decay rate of 14C is proportional to the amount of 14C in the sample. Therefore, we can write:

    (24/3)/(52/2) = (1/2)^(x/5730)

    Simplifying the equation, we get:

    x = 9,843.2 years

    Therefore, the age of the wood specimen is between 9600 and 9900 years.
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    A wood specimen containing 14C taken from an ancient palace showed 24 counts in 3 minutes per gram of carbon in a detector. However, a fresh wood showed 52 counts in 2 minutes per gram of carbon. Assuming no background signal in the detector and half life of 14C as 5730 years, the age (in years) of the wood specimen is _______Correct answer is between '9600,9900'. Can you explain this answer?
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    A wood specimen containing 14C taken from an ancient palace showed 24 counts in 3 minutes per gram of carbon in a detector. However, a fresh wood showed 52 counts in 2 minutes per gram of carbon. Assuming no background signal in the detector and half life of 14C as 5730 years, the age (in years) of the wood specimen is _______Correct answer is between '9600,9900'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A wood specimen containing 14C taken from an ancient palace showed 24 counts in 3 minutes per gram of carbon in a detector. However, a fresh wood showed 52 counts in 2 minutes per gram of carbon. Assuming no background signal in the detector and half life of 14C as 5730 years, the age (in years) of the wood specimen is _______Correct answer is between '9600,9900'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wood specimen containing 14C taken from an ancient palace showed 24 counts in 3 minutes per gram of carbon in a detector. However, a fresh wood showed 52 counts in 2 minutes per gram of carbon. Assuming no background signal in the detector and half life of 14C as 5730 years, the age (in years) of the wood specimen is _______Correct answer is between '9600,9900'. Can you explain this answer?.
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