A rivet joint in a structure shown in figure has to support a load of ...
Calculation of Maximum Stress developed in Rivet Joint
Given Data:
- Load to be supported: 2KN
- Primary Shear Stress: 6.37 MPa
- Secondary Shear Stress: 13.50 MPa
Formula:
Maximum stress developed in the rivet joint is given by the formula:
Maximum Stress = (Load/Shear Area) + (Load/Tensile Area)
where,
- Load: Load to be supported
- Shear Area: Cross-sectional area of the rivet in shear plane
- Tensile Area: Cross-sectional area of the rivet in tensile plane
Solution:
Let's assume the diameter of the rivet to be 'd' and thickness of plates to be 't'.
Shear Area:
The cross-sectional area of the rivet in shear plane is given by the formula:
Shear Area = (π/4) x d²
Tensile Area:
The cross-sectional area of the rivet in tensile plane is given by the formula:
Tensile Area = π x d x t
Maximum Stress:
Substituting the values in the formula of maximum stress, we get:
Maximum Stress = (2000/(π/4 x d²) + (2000/(π x d x t))
Maximum Stress = 256.04/d² + 204.20/(d x t)
Given, Primary Shear Stress = 6.37 MPa and Secondary Shear Stress = 13.50 MPa
We know that the maximum shear stress (τmax) is given by the formula:
τmax = √(τ^2 + 3/4 x σ^2)
where,
τ = Primary Shear Stress
σ = Secondary Shear Stress
Substituting the values, we get:
τmax = √(6.37^2 + 3/4 x 13.50^2)
τmax = 10.55 MPa
We know that the maximum tensile stress (σmax) is given by the formula:
σmax = Load/Tensile Area
Substituting the values, we get:
σmax = 2000/(π x d x t)
Equating τmax and σmax, we get:
10.55 = 2000/(π x d x t)
d x t = 2000/(π x 10.55)
d x t = 60.07 mm²
Assuming the thickness of plates 't' to be 10mm, we get:
d = 6.007 mm
Substituting the value of 'd' in the formula of maximum stress, we get:
Maximum Stress = 256.04/6.007² + 204.20/(6.007 x 10)
Maximum Stress = 31.99 MPa
Conclusion:
Therefore, the maximum stress developed in the rivet is 31.99 MPa.