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A rivet joint in a structure shown in figure has to support a load of 2KN . If the primary and secondary shear stress are 6.37 Mpa and 13.50Mpa respectively, the maximum stress developed in the rivet is Mpa?
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A rivet joint in a structure shown in figure has to support a load of ...
Calculation of Maximum Stress developed in Rivet Joint


Given Data:


  • Load to be supported: 2KN

  • Primary Shear Stress: 6.37 MPa

  • Secondary Shear Stress: 13.50 MPa



Formula:

Maximum stress developed in the rivet joint is given by the formula:

Maximum Stress = (Load/Shear Area) + (Load/Tensile Area)

where,

  • Load: Load to be supported

  • Shear Area: Cross-sectional area of the rivet in shear plane

  • Tensile Area: Cross-sectional area of the rivet in tensile plane



Solution:

Let's assume the diameter of the rivet to be 'd' and thickness of plates to be 't'.

Shear Area:

The cross-sectional area of the rivet in shear plane is given by the formula:

Shear Area = (π/4) x d²

Tensile Area:

The cross-sectional area of the rivet in tensile plane is given by the formula:

Tensile Area = π x d x t

Maximum Stress:

Substituting the values in the formula of maximum stress, we get:

Maximum Stress = (2000/(π/4 x d²) + (2000/(π x d x t))

Maximum Stress = 256.04/d² + 204.20/(d x t)

Given, Primary Shear Stress = 6.37 MPa and Secondary Shear Stress = 13.50 MPa

We know that the maximum shear stress (τmax) is given by the formula:

τmax = √(τ^2 + 3/4 x σ^2)

where,
τ = Primary Shear Stress
σ = Secondary Shear Stress

Substituting the values, we get:

τmax = √(6.37^2 + 3/4 x 13.50^2)

τmax = 10.55 MPa

We know that the maximum tensile stress (σmax) is given by the formula:

σmax = Load/Tensile Area

Substituting the values, we get:

σmax = 2000/(π x d x t)

Equating τmax and σmax, we get:

10.55 = 2000/(π x d x t)

d x t = 2000/(π x 10.55)

d x t = 60.07 mm²

Assuming the thickness of plates 't' to be 10mm, we get:

d = 6.007 mm

Substituting the value of 'd' in the formula of maximum stress, we get:

Maximum Stress = 256.04/6.007² + 204.20/(6.007 x 10)

Maximum Stress = 31.99 MPa

Conclusion:

Therefore, the maximum stress developed in the rivet is 31.99 MPa.
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A rivet joint in a structure shown in figure has to support a load of 2KN . If the primary and secondary shear stress are 6.37 Mpa and 13.50Mpa respectively, the maximum stress developed in the rivet is Mpa?
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A rivet joint in a structure shown in figure has to support a load of 2KN . If the primary and secondary shear stress are 6.37 Mpa and 13.50Mpa respectively, the maximum stress developed in the rivet is Mpa? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A rivet joint in a structure shown in figure has to support a load of 2KN . If the primary and secondary shear stress are 6.37 Mpa and 13.50Mpa respectively, the maximum stress developed in the rivet is Mpa? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rivet joint in a structure shown in figure has to support a load of 2KN . If the primary and secondary shear stress are 6.37 Mpa and 13.50Mpa respectively, the maximum stress developed in the rivet is Mpa?.
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