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A steel bar of 10 × 50 mm is cantilevered with two M12 bolts (P and Q) to support a static load of 4 kN as shown in the figure.
The primary and secondary shear loads on bolt P, respectively, are
- a)2 kN, 20 kN
- b)20 kN, 2 kN
- c)20 kN, 0 kN
- d)0 kN, 20 kN
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A steel bar of 10 × 50 mm is cantilevered with two M12 bolts (P ...
Let F1 and F2 resist the 4 kN eccentric oad. The primary shear load is due to a direct shear stress of 4kN, which is equally divided amongst the two bolts, i.e. 2 kN,
∴ Fprimary on P = 2 kN
∴ Fprimary on P = 2 kN
The secondary load is to resist the moment produced by the eccentric load 4 kN about the C.
G. of the joint
Moment M = 4 k N × 2000 mm
= 8000
Nm Now this moment must be balanced by a moment produced by equal and opposite forces i.e. secondary loads on the bolts i .e. F × 400 = 800 N m
⇒ F = 20 k N
Most Upvoted Answer
A steel bar of 10 × 50 mm is cantilevered with two M12 bolts (P ...
Let F1 and F2 resist the 4 kN eccentric oad. The primary shear load is due to a direct shear stress of 4kN, which is equally divided amongst the two bolts, i.e. 2 kN,
∴ Fprimary on P = 2 kN
∴ Fprimary on P = 2 kN
The secondary load is to resist the moment produced by the eccentric load 4 kN about the C.
G. of the joint
Moment M = 4 k N × 2000 mm
= 8000
Nm Now this moment must be balanced by a moment produced by equal and opposite forces i.e. secondary loads on the bolts i .e. F × 400 = 800 N m
⇒ F = 20 k N
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Community Answer
A steel bar of 10 × 50 mm is cantilevered with two M12 bolts (P ...
Let F1 and F2 resist the 4 kN eccentric oad. The primary shear load is due to a direct shear stress of 4kN, which is equally divided amongst the two bolts, i.e. 2 kN,
∴ Fprimary on P = 2 kN
∴ Fprimary on P = 2 kN
The secondary load is to resist the moment produced by the eccentric load 4 kN about the C.
G. of the joint
Moment M = 4 k N × 2000 mm
= 8000
Nm Now this moment must be balanced by a moment produced by equal and opposite forces i.e. secondary loads on the bolts i .e. F × 400 = 800 N m
⇒ F = 20 k N
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A steel bar of 10 × 50 mm is cantilevered with two M12 bolts (P and Q) to support a static load of 4 kN as shown in the figure.The primary and secondary shear loads on bolt P, respectively, area)2 kN, 20 kNb)20 kN, 2 kNc)20 kN, 0 kNd)0 kN, 20 kNCorrect answer is option 'A'. Can you explain this answer?
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