A first order reaction is 87.5% complete at the end of 30 minutes. The...
Explanation:
Given, the reaction is first order. Let's consider the rate law for a first order reaction:
k = (2.303/t) log(C₀/Ct)
Where k is the rate constant, t is time, C₀ is the initial concentration, and Ct is the concentration at time t.
Step 1: Finding the fraction of the reactant remaining after 30 minutes.
Given that the reaction is 87.5% complete at the end of 30 minutes, the fraction of the reactant remaining after 30 minutes can be calculated as follows:
Fraction of the reactant remaining = 1 - 0.875 = 0.125
Step 2: Finding the value of k.
We know that the reaction is first order, and the rate constant k can be determined using the half-life of the reaction. We can use the following formula to calculate the value of k:
ln(2)/k = t½
Where ln(2) is the natural logarithm of 2, and t½ is the half-life of the reaction.
From the given information, we know that the reaction is 50% complete at the end of the half-life. Therefore, the time taken for the reaction to reach 50% completion is the half-life of the reaction.
Let's assume that the half-life of the reaction is t½.
Then, at t = t½, Ct = C₀/2
Substituting the values in the rate law equation, we get:
k = (2.303/t½) log(C₀/(C₀/2))
k = (2.303/t½) log(2)
k = 0.693/t½
Step 3: Finding the value of t½.
Substituting the value of k in the equation for half-life, we get:
ln(2)/(0.693/t½) = t½
t½ = ln(2)/0.693
t½ = 0.693/k
Substituting the value of k, we get:
t½ = 0.693/(0.693/t½)
t½ = t½
Therefore, the half-life of the reaction is independent of the rate constant k.
Step 4: Finding the half-life of the reaction.
We know that the reaction is 87.5% complete at the end of 30 minutes. Using the fraction of the reactant remaining, we can write:
Ct/C₀ = 0.125
Substituting the value of Ct in the rate law equation, we get:
k = (2.303/30) log(C₀/(0.125C₀))
k = 2.303/30 * log(8)
k = 0.0234 min⁻¹
Substituting the value of k in the equation for half-life, we get:
t½ = 0.693/0.0234
t½ = 29.6 minutes
Therefore, the half-life of the reaction is approximately 30 minutes.
Answer:
The half-life of the reaction is between 9.8 to 10.2 minutes.
A first order reaction is 87.5% complete at the end of 30 minutes. The...