The solubility of PbI_{2} in 0.10 M KI(aq) is ______ ×10^{–7} M (rounded up to two decimal places).

[The solubility product,_{sp} = 7.1×10^{–9}]

[The solubility product,

Correct answer is between '7.0,7.2'. Can you explain this answer?

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