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A person has 45 coins of 50p, 1 rupee and 2 rupee coins in ratio 6 : 2 : 1. Which of the following combinations will yield the same amount of total money (the order of is 25p, 50p and 1 rupee and the total number of coins).
  • a)
    6, 2, 1, 45
  • b)
    6, 2, 1, 80
  • c)
    6, 5, 3, 70
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A person has 45 coins of 50p, 1 rupee and 2 rupee coins in ratio 6 : 2...
Actual money with the person = 0.5((6/9) × 45) + 1((2/9) × 45) + 2((1/9) × 45) = 15 + 10 + 10 = Rs. 35
Total money in First case:
Total value of coins = 0.25((6/9) × 45) + 0.50((2/9) × 45) + 1((2/9) × 45) = 7.5 + 5 + 10 = Rs. 22.50
Total money in Second case:
Total value of coins = 0.25((6/9) × 90) + 0.50((2/9) × 90) + 1((2/9) × 90) = Rs. 45
Total money in Third case:
Total value of coins = 0.25((6/14) × 70) + 0.50((5/14) × 70) + 1((3/14) × 70) = Rs. 35
In third case, the amount is same
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Most Upvoted Answer
A person has 45 coins of 50p, 1 rupee and 2 rupee coins in ratio 6 : 2...

Explanation:

Given information:
- The person has 45 coins in total, consisting of 50p, 1 rupee, and 2 rupee coins.
- The coins are in the ratio 6 : 2 : 1.

Calculation:
- Let the number of 50p coins be 6x, 1 rupee coins be 2x, and 2 rupee coins be x.
- Total number of coins = 6x + 2x + x = 9x = 45
- x = 5

Calculating total money for each case:
- Total money in the first case = 6(0.50) + 2(1) + 1(2) = 3 + 2 + 2 = 7
- Total money in the second case = 6(0.50) + 2(1) + 1(2) = 3 + 2 + 2 = 7
- Total money in the third case = 6(0.50) + 5(1) + 3(2) = 3 + 5 + 6 = 14

Conclusion:
- The combination that yields the same total money is option C: 6, 5, 3, 70.
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A person has 45 coins of 50p, 1 rupee and 2 rupee coins in ratio 6 : 2 : 1. Which of the following combinations will yield the same amount of total money (the order of is 25p, 50p and 1 rupee and the total number of coins).a)6, 2, 1, 45b)6, 2, 1, 80c)6, 5, 3, 70d)None of theseCorrect answer is option 'C'. Can you explain this answer?
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