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An ammeter gives full deflection when a current of 2 amp. flows through it. The resistance of ammeter is 12 ohms. If the same ammeter is to be used for measuring a maximum current of 5 amp., then the ammeter must be connected with a resistance of
  • a)
    8 ohms in series
  • b)
    18 ohms in series
  • c)
    8 ohms in parallel
  • d)
    18 ohms in parallel
Correct answer is option 'C'. Can you explain this answer?
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An ammeter gives full deflection when a current of 2 amp. flows throug...
Solution:

Given, full deflection current, I = 2 A and ammeter resistance, R = 12 Ω

Let the resistance to be connected in parallel with the ammeter be R'.

Let the maximum current that can be measured by the ammeter be Imax = 5 A.

To find: The value of R' to be connected in parallel with the ammeter.

Using the ammeter and R', a parallel combination is formed, which can be represented as shown below.

Let I' be the current that flows through the parallel combination.

From Kirchhoff's current law, the current I flowing through the circuit is given by:

I = I' + Imax

As per the question, the ammeter gives full deflection when the current is 2 A.

Therefore, the current through the ammeter, Ia = 2 A.

From Ohm's law, the potential difference across the ammeter, Va = Ia × R = 2 × 12 = 24 V.

The potential difference across the parallel combination, V' = Va.

From Ohm's law, the current I' flowing through the parallel combination is given by:

I' = V' / R'

Substituting the values of V' and I' in the equation obtained above, we get:

I = V' / R' + Imax

Substituting the values of I, V' and Imax in the above equation, we get:

5 = 24 / R' + 2

Solving the above equation for R', we get:

R' = 8 Ω

Therefore, the value of R' to be connected in parallel with the ammeter is 8 Ω.

Hence, option C is the correct answer.
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