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There are 10 points in a plane of which no three points are collinear and 4 points are concyclic. The number of different circles that can be drawn through at least 3 points of these points is
  • a)
    116
  • b)
    120
  • c)
    117
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
There are 10 points in a plane of which no three points are collinear ...
The number of circles = (10C3-4C3) + 1
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There are 10 points in a plane of which no three points are collinear and 4 points are concyclic. The number of different circles that can be drawn through at least 3 points of these points isa)116b)120c)117d)none of theseCorrect answer is option 'C'. Can you explain this answer?
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