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The total number of ways in which six '+' and four '-' signs can be arrange in a line such that no two ‘-' signs occur together is
  • a)
    7!/3!
  • b)
    6! x 7!/3!
  • c)
    35
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The total number of ways in which six + and four - signs can be arrang...
'-' signs will be put between two '+’ signs or at the two ends.
There arc 7 places for four '-' signs. So, the required number of ways

(there being no arrangement as the '+' signs are identical as well '-' as signs arc identical).
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Most Upvoted Answer
The total number of ways in which six + and four - signs can be arrang...
'-' signs will be put between two '+’ signs or at the two ends.
There arc 7 places for four '-' signs. So, the required number of ways

(there being no arrangement as the '+' signs are identical as well '-' as signs arc identical).
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The total number of ways in which six + and four - signs can be arrange in a line such that no two ‘- signs occur together isa)7!/3!b)6! x 7!/3!c)35d)none of theseCorrect answer is option 'C'. Can you explain this answer?
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