Number of Numbers Divisible by 3:
To find the number of numbers divisible by 3 that can be formed using four different even digits, we need to consider the divisibility rule for 3. According to the rule, a number is divisible by 3 if the sum of its digits is divisible by 3.

Combination of Even Digits:
Since we are using four different even digits, we have a total of 4 choices for the first digit, 3 choices for the second digit, 2 choices for the third digit, and 1 choice for the fourth digit. Therefore, the total number of possible combinations is 4 × 3 × 2 × 1 = 24.

Divisibility by 3:
In order for a number to be divisible by 3, the sum of its digits must be divisible by 3. Since the digits are even, the possible sums of digits are 2, 4, 6, and 8.

Sum of Digits:
In order to form a number divisible by 3, we need to consider the possible sums of digits and check if any of them are divisible by 3.

- Sum of digits = 2 + 4 + 6 + 8 = 20 (not divisible by 3)
- Sum of digits = 2 + 4 + 8 + 6 = 20 (not divisible by 3)
- Sum of digits = 2 + 6 + 4 + 8 = 20 (not divisible by 3)
- Sum of digits = 2 + 6 + 8 + 4 = 20 (not divisible by 3)
- Sum of digits = 2 + 8 + 4 + 6 = 20 (not divisible by 3)
- Sum of digits = 2 + 8 + 6 + 4 = 20 (not divisible by 3)
- Sum of digits = 4 + 2 + 6 + 8 = 20 (not divisible by 3)
- Sum of digits = 4 + 2 + 8 + 6 = 20 (not divisible by 3)
- Sum of digits = 4 + 6 + 2 + 8 = 20 (not divisible by 3)
- Sum of digits = 4 + 6 + 8 + 2 = 20 (not divisible by 3)
- Sum of digits = 4 + 8 + 2 + 6 = 20 (not divisible by 3)
- Sum of digits = 4 + 8 + 6 + 2 = 20 (not divisible by 3)
- Sum of digits = 6 + 2 + 4 + 8 = 20 (not divisible by 3)
- Sum of digits = 6 + 2 + 8 + 4 = 20 (not divisible by 3)
- Sum of digits = 6 + 4 + 2 + 8 = 20 (not divisible by 3)
- Sum of digits = 6 + 4 + 8 + 2 = 20 (not divisible by 3)
- Sum of digits = 6 + 8 + 2 + 4 = 20 (not divisible by 3)
- Sum of digits =