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The number of geometric isomers that can exist for square planar [Pt(Cl)(py)(NH3)(NH2OH)]+ is (py = pyridine)
- a)2
- b)3
- c)4
- d)6
Correct answer is option 'B'. Can you explain this answer?
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The number of geometric isomers that can exist for square planar [Pt(C...
as per question a = Cl, b = py, c = NH3 and d = NH2OH are assumed.
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The number of geometric isomers that can exist for square planar [Pt(C...
Geometric Isomers for [Pt(Cl)(py)(NH3)(NH2OH)]+
First, let's determine the possible geometric isomers for the given square planar complex [Pt(Cl)(py)(NH3)(NH2OH)]+.
1. Geometric Isomer #1:
In this isomer, the pyridine (py) and NH3 ligands are adjacent to each other in a cis configuration, while the Cl and NH2OH ligands are on the opposite sides in a trans configuration.
2. Geometric Isomer #2:
In this isomer, the pyridine (py) and NH3 ligands are on opposite sides in a trans configuration, while the Cl and NH2OH ligands are adjacent to each other in a cis configuration.
3. Geometric Isomer #3:
In this isomer, the Cl and pyridine (py) ligands are adjacent to each other in a cis configuration, while the NH3 and NH2OH ligands are on the opposite sides in a trans configuration.
Therefore, there are a total of 3 possible geometric isomers that can exist for the square planar complex [Pt(Cl)(py)(NH3)(NH2OH)]+. Hence, the correct answer is option 'B' - 3.
First, let's determine the possible geometric isomers for the given square planar complex [Pt(Cl)(py)(NH3)(NH2OH)]+.
1. Geometric Isomer #1:
In this isomer, the pyridine (py) and NH3 ligands are adjacent to each other in a cis configuration, while the Cl and NH2OH ligands are on the opposite sides in a trans configuration.
2. Geometric Isomer #2:
In this isomer, the pyridine (py) and NH3 ligands are on opposite sides in a trans configuration, while the Cl and NH2OH ligands are adjacent to each other in a cis configuration.
3. Geometric Isomer #3:
In this isomer, the Cl and pyridine (py) ligands are adjacent to each other in a cis configuration, while the NH3 and NH2OH ligands are on the opposite sides in a trans configuration.
Therefore, there are a total of 3 possible geometric isomers that can exist for the square planar complex [Pt(Cl)(py)(NH3)(NH2OH)]+. Hence, the correct answer is option 'B' - 3.
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The number of geometric isomers that can exist for square planar [Pt(Cl)(py)(NH3)(NH2OH)]+ is (py = pyridine)a)2b)3c)4d)6Correct answer is option 'B'. Can you explain this answer?
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