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If M and N are functions of x and y, then the equation Mdx + Ndy = 0 is exact if
  • a)
      a function f(x, y) of x and y such that f (x, y) = Mdx + Ndy
  • b)
      a function f(x, y) of x and y such that 
  • c)
     a function u(x) of x alone such that d[u(x)] = Mdx + Ndy
  • d)
      a function v(y) of y alone such that d[v(y)] = Mdx + Ndy
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If M and N are functions of xand y, then the equation Mdx + Ndy = 0 is...
The necessary and sufficient condition for the differential equation
M(x, y)dx + N(x, y)dy = 0 to be exact is that

Proof: Condition


Remark : An exact differential equation can be written as du = 0. where u is some function of x and y.
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Most Upvoted Answer
If M and N are functions of xand y, then the equation Mdx + Ndy = 0 is...
The necessary and sufficient condition for the differential equation
M(x, y)dx + N(x, y)dy = 0 to be exact is that

Proof: Condition


Remark : An exact differential equation can be written as du = 0. where u is some function of x and y.
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If M and N are functions of xand y, then the equation Mdx + Ndy = 0 is exact ifa)a function f(x, y) of x and y such that f (x,y) = Mdx +Ndyb)a function f(x, y) of xand y such thatc)a function u(x) of xalone such thatd[u(x)]= Mdx + Ndyd)a function v(y) of y alone such that d[v(y)] = Mdx + NdyCorrect answer is option 'B'. Can you explain this answer?
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