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Let U= {1, 2, 3, 4, 5.} A subset S is chosen uniformly at random from the non-empty subsets of U. What is the probability that S does NOT have two consecutive elements?
  • a)
    9/31
  • b)
    10/31
  • c)
    11/31
  • d)
    12/31
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Let U= {1, 2, 3, 4, 5.} A subset S is chosen uniformly at random from ...
Given 
u={1,2,3,4,5}.

a non-empty subset of U. = 31

1 , 2 , 3 , 4 , 5 , (1,2) ,(1,3) ,(1,4) ,(1,5) ,(2,3) ,(2,4) (2,5) ,(3,4),(3,5) ,(4,5) ,(1,2 ,3) ,(1,2,4) ,(1,2,5) , (1,3 ,4) ,(1,3,5) ,( 1,4,5) ,(2,3 ,4) ,(2,3,5) ,(2,4,5) ,(3,4,5) ,(1,2,3,4) ,(1,2,3,5) (1,2,4,5),(1,3,4,5) ,(2,3,4,5) ,(1,2,3,4,5)

A subset S is chosen uniformly at random from a does not have two consecutive elements

= 12

probability at S does not have two consecutive elements = (12/31)

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Most Upvoted Answer
Let U= {1, 2, 3, 4, 5.} A subset S is chosen uniformly at random from ...
To find the probability that a randomly chosen subset S from U does not have two consecutive elements, we can consider the number of subsets that do not have two consecutive elements and divide it by the total number of non-empty subsets.

Total number of non-empty subsets:
The set U has 5 elements, so the total number of subsets (including the empty set) is 2^5 = 32. However, we need to subtract 1 from this total to exclude the empty set, so the total number of non-empty subsets is 32 - 1 = 31.

Number of subsets that do not have two consecutive elements:
To count the number of subsets that do not have two consecutive elements, we can use a recursive approach. Let's define a function f(n) as the number of such subsets for a set of size n.

For n = 1, there is only one subset {1} that does not have two consecutive elements, so f(1) = 1.
For n = 2, there are two subsets {1} and {2} that do not have two consecutive elements, so f(2) = 2.
For n > 2, we can consider two cases:
1. The subset does not include the last element (n). In this case, we can choose any subset that does not have two consecutive elements from the set {1, 2, ..., n-1}, which is equivalent to f(n-1).
2. The subset includes the last element (n). In this case, the second-to-last element (n-1) cannot be included in the subset, so we need to choose any subset that does not have two consecutive elements from the set {1, 2, ..., n-2}, which is equivalent to f(n-2).

Therefore, we can define the recursive formula for f(n) as:
f(n) = f(n-1) + f(n-2)

Using this formula, we can calculate the values of f(n) for n = 1, 2, 3, 4, 5:
f(1) = 1
f(2) = 2
f(3) = f(2) + f(1) = 2 + 1 = 3
f(4) = f(3) + f(2) = 3 + 2 = 5
f(5) = f(4) + f(3) = 5 + 3 = 8

Therefore, the number of subsets that do not have two consecutive elements is f(5) = 8.

Probability calculation:
The probability that S does not have two consecutive elements can be calculated by dividing the number of subsets that do not have two consecutive elements by the total number of non-empty subsets:

Probability = number of subsets that do not have two consecutive elements / total number of non-empty subsets
Probability = 8 / 31

Therefore, the correct answer is option D) 8/31, not option D) 12/31 as stated in the question.
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Let U= {1, 2, 3, 4, 5.} A subset S is chosen uniformly at random from the non-empty subsets of U. What is the probability that S does NOT have two consecutive elements?a)9/31b)10/31c)11/31d)12/31Correct answer is option 'D'. Can you explain this answer?
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