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Consider two ligands A and B which can bind to receptor R either individually or simultaneously. The probability that A can bind to R is 0.10, and probability that B can bind to R is 0.20. The probability that both A and B can bind to R is 0.05. The probability that both A and B will NOT bind to R is ______
Correct answer is between '0.74,0.76'. Can you explain this answer?
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Consider two ligands A and B which can bind to receptor R either indiv...
Solution:
Given probabilities:
- P(A) = 0.10
- P(B) = 0.20
- P(A and B) = 0.05
We need to find the probability that both A and B will NOT bind to R.
Step 1: Find the probability that at least one of A or B will bind to R.
P(A or B) = P(A) + P(B) - P(A and B)
= 0.10 + 0.20 - 0.05
= 0.25
Step 2: Find the probability that both A and B will NOT bind to R.
P(not A and not B) = 1 - P(A or B)
= 1 - 0.25
= 0.75
Therefore, the probability that both A and B will NOT bind to R is 0.75 or 0.74-0.76 (approximate range).
Given probabilities:
- P(A) = 0.10
- P(B) = 0.20
- P(A and B) = 0.05
We need to find the probability that both A and B will NOT bind to R.
Step 1: Find the probability that at least one of A or B will bind to R.
P(A or B) = P(A) + P(B) - P(A and B)
= 0.10 + 0.20 - 0.05
= 0.25
Step 2: Find the probability that both A and B will NOT bind to R.
P(not A and not B) = 1 - P(A or B)
= 1 - 0.25
= 0.75
Therefore, the probability that both A and B will NOT bind to R is 0.75 or 0.74-0.76 (approximate range).
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Consider two ligands A and B which can bind to receptor R either individually or simultaneously. The probability that A can bind to R is 0.10, and probability that B can bind to R is 0.20. The probability that both A and B can bind to R is 0.05. The probability that both A and B will NOT bind to R is ______Correct answer is between '0.74,0.76'. Can you explain this answer?
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