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Two dice are thrown simultaneously. The probability that the sum of the number obtained is divisible by 7 is
- a)1/6
- b)1/36
- c)0
- d)1/18
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Two dice are thrown simultaneously. The probability that the sum of th...
Solution:
When two dice are thrown simultaneously, the total number of outcomes = 6 x 6 = 36.
We need to find the probability that the sum of the numbers obtained is divisible by 7.
Let's list all possible outcomes of throwing two dice:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Now, let's find the pairs of outcomes whose sum is divisible by 7:
(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)
There are 6 such pairs of outcomes.
Therefore, the required probability = 6/36 = 1/6.
Therefore, option 'A' is the correct answer.
When two dice are thrown simultaneously, the total number of outcomes = 6 x 6 = 36.
We need to find the probability that the sum of the numbers obtained is divisible by 7.
Let's list all possible outcomes of throwing two dice:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Now, let's find the pairs of outcomes whose sum is divisible by 7:
(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)
There are 6 such pairs of outcomes.
Therefore, the required probability = 6/36 = 1/6.
Therefore, option 'A' is the correct answer.
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Community Answer
Two dice are thrown simultaneously. The probability that the sum of th...
Soln.
n(s) =6×6=36
E={(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}
n(E) =6
P(E) =6/36=1/6.
n(s) =6×6=36
E={(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}
n(E) =6
P(E) =6/36=1/6.
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