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Out of 5 computers scientist and 7 mathematician a committee consisting of 2 computer scientists and 3 mathematicians is to be formed. The number of ways in which this can be done if any computer scientists and any mathematician can be included is :
  • a)
    250 ways
  • b)
    450 ways
  • c)
    150 ways
  • d)
    350 ways
Correct answer is option 'D'. Can you explain this answer?
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Out of 5 computers scientist and 7 mathematician a committee consistin...
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Out of 5 computers scientist and 7 mathematician a committee consistin...
To find the number of ways in which the committee can be formed, we need to consider the combinations of computer scientists and mathematicians that can be included.

Total number of computer scientists = 5
Total number of mathematicians = 7

We need to form a committee consisting of 2 computer scientists and 3 mathematicians.

Step 1: Selecting 2 computer scientists
The number of ways to select 2 computer scientists out of 5 is given by the combination formula:

C(5, 2) = 5! / (2! * (5-2)!) = 5! / (2! * 3!) = (5 * 4) / (2 * 1) = 10

Step 2: Selecting 3 mathematicians
The number of ways to select 3 mathematicians out of 7 is given by the combination formula:

C(7, 3) = 7! / (3! * (7-3)!) = 7! / (3! * 4!) = (7 * 6 * 5) / (3 * 2 * 1) = 35

Step 3: Combining the selections
To find the total number of ways to form the committee, we multiply the number of ways to select computer scientists and mathematicians:

Total number of ways = 10 * 35 = 350

Therefore, the correct answer is option D) 350 ways.
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Out of 5 computers scientist and 7 mathematician a committee consisting of 2 computer scientists and 3 mathematicians is to be formed. The number of ways in which this can be done if any computer scientists and any mathematician can be included is :a)250 waysb)450 waysc)150 waysd)350 waysCorrect answer is option 'D'. Can you explain this answer?
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