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For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in the
temperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, the
temperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.
temperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, the
temperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.
Imp : you should answer only the numeric value
Correct answer is '310'. Can you explain this answer?
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Given:
- Rate of change of vapour pressure with temperature = 0.1 bar/K
- Temperature range = 300 to 350 K
- Boiling point at 2 bar pressure = 320 K
To find: Temperature at which the liquid will boil at 1 bar pressure
Solution:
- Let's assume that the boiling point of the liquid at 1 bar pressure is T1.
- At 2 bar pressure, the boiling point is 320 K. This means that at 320 K, the vapour pressure of the liquid is 2 bar.
- Using the Clausius-Clapeyron equation, we can find the vapour pressure of the liquid at T1 temperature as follows:
ln(P1/P2) = ΔHvap/R * (1/T2 - 1/T1)
where,
- P1 = vapour pressure at T1
- P2 = vapour pressure at 320 K (2 bar)
- ΔHvap = enthalpy of vaporization
- R = gas constant
- T2 = boiling point temperature at 2 bar pressure (320 K)
- We can simplify the equation by assuming that ΔHvap and R are constant, and by using the given rate of change of vapour pressure with temperature:
ln(P1/2) = ΔHvap/R * (1/320 - 1/T1)
ln(P1/2) = -0.1 * ΔHvap/R
P1/2 = e^(-0.1 * ΔHvap/R)
- Now, we can solve for P1 by using the fact that at 1 bar pressure, the liquid is boiling:
P1 = 1 bar
- Substituting this value in the above equation:
1/2 = e^(-0.1 * ΔHvap/R)
ln(1/2) = -0.1 * ΔHvap/R
ΔHvap = -R * ln(1/2) / 0.1
- We can now use the value of ΔHvap to solve for T1:
ln(P1/P2) = ΔHvap/R * (1/T2 - 1/T1)
ln(1/2) = ΔHvap/R * (1/320 - 1/T1)
T1 = 1 / (ln(1/2) / ΔHvap/R + 1/320)
- Plugging in the values, we get:
T1 = 310 K (rounded to one decimal place)
Answer: 310
- Rate of change of vapour pressure with temperature = 0.1 bar/K
- Temperature range = 300 to 350 K
- Boiling point at 2 bar pressure = 320 K
To find: Temperature at which the liquid will boil at 1 bar pressure
Solution:
- Let's assume that the boiling point of the liquid at 1 bar pressure is T1.
- At 2 bar pressure, the boiling point is 320 K. This means that at 320 K, the vapour pressure of the liquid is 2 bar.
- Using the Clausius-Clapeyron equation, we can find the vapour pressure of the liquid at T1 temperature as follows:
ln(P1/P2) = ΔHvap/R * (1/T2 - 1/T1)
where,
- P1 = vapour pressure at T1
- P2 = vapour pressure at 320 K (2 bar)
- ΔHvap = enthalpy of vaporization
- R = gas constant
- T2 = boiling point temperature at 2 bar pressure (320 K)
- We can simplify the equation by assuming that ΔHvap and R are constant, and by using the given rate of change of vapour pressure with temperature:
ln(P1/2) = ΔHvap/R * (1/320 - 1/T1)
ln(P1/2) = -0.1 * ΔHvap/R
P1/2 = e^(-0.1 * ΔHvap/R)
- Now, we can solve for P1 by using the fact that at 1 bar pressure, the liquid is boiling:
P1 = 1 bar
- Substituting this value in the above equation:
1/2 = e^(-0.1 * ΔHvap/R)
ln(1/2) = -0.1 * ΔHvap/R
ΔHvap = -R * ln(1/2) / 0.1
- We can now use the value of ΔHvap to solve for T1:
ln(P1/P2) = ΔHvap/R * (1/T2 - 1/T1)
ln(1/2) = ΔHvap/R * (1/320 - 1/T1)
T1 = 1 / (ln(1/2) / ΔHvap/R + 1/320)
- Plugging in the values, we get:
T1 = 310 K (rounded to one decimal place)
Answer: 310
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For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer?
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For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer?.
For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer?.
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For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer?, a detailed solution for For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer? has been provided alongside types of For a pure liquid, the rate of change of vapour pressure with temperature is 0.1 bar/K in thetemperature range of 300 to 350 K. if the boiling point of the liquid at 2 bar is 320 K, thetemperature (in K) at which it will boil at 1 bar (up to one decimal place) is ___________.Imp : you should answer only the numeric valueCorrect answer is '310'. Can you explain this answer? theory, EduRev gives you an
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