Class 11 Exam > Class 11 Questions > Q.No-11-35 Carry One Mark EachBenzene is remo...
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Q.No-11-35 Carry One Mark Each
Benzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrent
gas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. The
flow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50
kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steady
state. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow rates
of liquid and gas phases inside the column.’
For this process, the value of the absorption factor (upto two decimal places) is _________.
gas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. The
flow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50
kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steady
state. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow rates
of liquid and gas phases inside the column.’
For this process, the value of the absorption factor (upto two decimal places) is _________.
Imp : you should answer only the numeric value
Correct answer is '1.02'. Can you explain this answer?
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Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing...
To solve this problem, we can use the concept of equilibrium between the gas and liquid phases.
Let's denote the moles of benzene in the gas phase as nBenzene_gas and in the liquid phase as nBenzene_liquid.
Similarly, let's denote the moles of wash-oil in the gas phase as nWashOil_gas and in the liquid phase as nWashOil_liquid.
Since benzene forms an ideal solution with the wash-oil, we can assume that the mole fraction of benzene in the liquid phase (x_benzene) is the same as the mole fraction of benzene in the gas phase (y_benzene).
Given:
Gas flow rate (n_gas) = 100 mol/min
Mole flow rate of benzene (nBenzene_gas) = 2 mol/min
Flow rate of wash-oil (nWashOil_gas) = 50 mol/min
Vapour pressure of benzene (P_benzene) = 50 kPa
Using the ideal gas law, we can calculate the mole fraction of benzene in the gas phase:
y_benzene = nBenzene_gas / n_gas = 2 mol/min / 100 mol/min = 0.02
Since the column is operating at steady state, the mole fraction of benzene in the liquid phase (x_benzene) can be calculated using the equilibrium relationship:
P_benzene = x_benzene * P_total
where P_total is the total pressure of the column, which is 100 kPa.
Plugging in the values:
50 kPa = x_benzene * 100 kPa
x_benzene = 0.5
Since the mole fraction of benzene in the liquid phase is the same as in the gas phase, we have:
x_benzene = y_benzene = 0.5
The flow rate of benzene in the liquid phase can be calculated using the total flow rate of wash-oil:
nBenzene_liquid = x_benzene * nWashOil_liquid = 0.5 * 50 mol/min = 25 mol/min
Therefore, the flow rate of benzene in the liquid phase is 25 mol/min.
Let's denote the moles of benzene in the gas phase as nBenzene_gas and in the liquid phase as nBenzene_liquid.
Similarly, let's denote the moles of wash-oil in the gas phase as nWashOil_gas and in the liquid phase as nWashOil_liquid.
Since benzene forms an ideal solution with the wash-oil, we can assume that the mole fraction of benzene in the liquid phase (x_benzene) is the same as the mole fraction of benzene in the gas phase (y_benzene).
Given:
Gas flow rate (n_gas) = 100 mol/min
Mole flow rate of benzene (nBenzene_gas) = 2 mol/min
Flow rate of wash-oil (nWashOil_gas) = 50 mol/min
Vapour pressure of benzene (P_benzene) = 50 kPa
Using the ideal gas law, we can calculate the mole fraction of benzene in the gas phase:
y_benzene = nBenzene_gas / n_gas = 2 mol/min / 100 mol/min = 0.02
Since the column is operating at steady state, the mole fraction of benzene in the liquid phase (x_benzene) can be calculated using the equilibrium relationship:
P_benzene = x_benzene * P_total
where P_total is the total pressure of the column, which is 100 kPa.
Plugging in the values:
50 kPa = x_benzene * 100 kPa
x_benzene = 0.5
Since the mole fraction of benzene in the liquid phase is the same as in the gas phase, we have:
x_benzene = y_benzene = 0.5
The flow rate of benzene in the liquid phase can be calculated using the total flow rate of wash-oil:
nBenzene_liquid = x_benzene * nWashOil_liquid = 0.5 * 50 mol/min = 25 mol/min
Therefore, the flow rate of benzene in the liquid phase is 25 mol/min.
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Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer?
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Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer?.
Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer?.
Solutions for Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer?, a detailed solution for Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer? has been provided alongside types of Q.No-11-35 Carry One Mark EachBenzene is removed from air by absorbing it in a non-volatile wash-oil at 100kPa in a countercurrentgas absorber. Gas flow rate is 100 mol/min, which includes 2 mol/min of benzene. Theflow rate of wash-oil is 50 mol/min.Vapour pressure of benzene at the column conditions is 50kPa. Benzene forms an ideal solution with the wash-oil and the column is operating at steadystate. Gas phase can be assumed to follow ideal gas law. Neglect the change in molar flow ratesof liquid and gas phases inside the column.’For this process, the value of the absorption factor (upto two decimal places) is _________.Imp : you should answer only the numeric valueCorrect answer is '1.02'. Can you explain this answer? theory, EduRev gives you an
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