Question Description
Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer?.

Solutions for Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer?, a detailed solution for Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer? has been provided alongside types of Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Suppose anucleus at rest and in ground state undergoes α-decay to anucleus in its excitedstate. The kinetic energy of the emitted α particle is found to be 4.44 MeV.nucleus then goesto its ground state by γ-decay. The energy of the emitted γ-photon is _______ keV,[Given: atomic mass ofatomic mass ofatomic mass of αparticle = 4.000u, 1u = 931 MeV/c2, c is speed of the light]Correct answer is '135.00'. Can you explain this answer? tests, examples and also practice JEE tests.