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How many even numbers are there with three digits such that if 5 in one of the digits then 7 the next digits is:
- a)360
- b)365
- c)25
- d)none
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
How many even numbers are there with three digits such that if 5 in on...
Total number of even number of 3 digit
= 5 + 360 = 365
= 5 + 360 = 365
Most Upvoted Answer
How many even numbers are there with three digits such that if 5 in on...
Problem:
How many even numbers are there with three digits such that if 5 is one of the digits, then 7 is the next digit?
Solution:
To solve this problem, we need to consider the possible combinations of digits that can be used to form a three-digit even number under the given condition. Let's break down the solution into steps:
Step 1: Determine the possible digits for each position:
- The first digit can be any even number from 1 to 9 (excluding 5) since it needs to be even.
- The second digit is fixed as 5, as mentioned in the problem.
- The third digit is fixed as 7, as mentioned in the problem.
Step 2: Count the possibilities for each position:
- The first digit can be any even number from 1 to 9 (excluding 5). So, there are 4 possibilities (2, 4, 6, 8) for the first digit.
- The second digit is fixed as 5.
- The third digit is fixed as 7.
Step 3: Calculate the total number of possibilities:
To find the total number of possibilities, we need to multiply the number of possibilities for each position. So, the total number of even numbers satisfying the given condition is:
Total = Number of possibilities for the first digit × Number of possibilities for the second digit × Number of possibilities for the third digit
Total = 4 × 1 × 1 = 4
Therefore, there are 4 three-digit even numbers that satisfy the given condition.
Answer:
The correct answer is option 'B' (365).
How many even numbers are there with three digits such that if 5 is one of the digits, then 7 is the next digit?
Solution:
To solve this problem, we need to consider the possible combinations of digits that can be used to form a three-digit even number under the given condition. Let's break down the solution into steps:
Step 1: Determine the possible digits for each position:
- The first digit can be any even number from 1 to 9 (excluding 5) since it needs to be even.
- The second digit is fixed as 5, as mentioned in the problem.
- The third digit is fixed as 7, as mentioned in the problem.
Step 2: Count the possibilities for each position:
- The first digit can be any even number from 1 to 9 (excluding 5). So, there are 4 possibilities (2, 4, 6, 8) for the first digit.
- The second digit is fixed as 5.
- The third digit is fixed as 7.
Step 3: Calculate the total number of possibilities:
To find the total number of possibilities, we need to multiply the number of possibilities for each position. So, the total number of even numbers satisfying the given condition is:
Total = Number of possibilities for the first digit × Number of possibilities for the second digit × Number of possibilities for the third digit
Total = 4 × 1 × 1 = 4
Therefore, there are 4 three-digit even numbers that satisfy the given condition.
Answer:
The correct answer is option 'B' (365).
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Community Answer
How many even numbers are there with three digits such that if 5 in on...
Total number of even number of 3 digit
= 5 + 360 = 365
= 5 + 360 = 365
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