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By X-ray diffraction methods, the unit length of NaCl is observed to be 0.5627 nm. The density of NaCl is found to be 2.164 g cm–3. The percentage of Na+ and Cl– ions missing is ____________%: (rounded up to 2 decimal place)
Correct answer is between '0.72,0.78'. Can you explain this answer?
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By X-ray diffraction methods, the unit length of NaCl is observed to b...
The density of NaCl can be calculated using the formula:
Density = mass / volume
The mass of NaCl can be calculated by multiplying the molar mass of NaCl (58.44 g/mol) by the number of moles.
The volume of NaCl can be calculated using the formula:
Volume = (unit length)^3
Given that the unit length of NaCl is 0.5627 nm, we need to convert it to cm:
0.5627 nm * (1 cm / 10^7 nm) = 5.627 x 10^-9 cm
Now we can calculate the volume:
Volume = (5.627 x 10^-9 cm)^3 = 1.001 x 10^-25 cm^3
Now we can calculate the mass:
Mass = number of moles * molar mass
Assuming we are dealing with 1 mole of NaCl:
Mass = 1 mol * 58.44 g/mol = 58.44 g
Finally, we can calculate the density:
Density = mass / volume = 58.44 g / 1.001 x 10^-25 cm^3
Since the density is given in g/cm^3, we need to convert the volume to cm^3:
1.001 x 10^-25 cm^3 * (10^3 cm^3 / 1 mL) * (1 mL / 1 cm^3) = 1.001 x 10^-22 g/cm^3
Density = 58.44 g / 1.001 x 10^-22 g/cm^3 = 5.830 x 10^21 g/cm^3
Therefore, the density of NaCl is approximately 5.830 x 10^21 g/cm^3.
Density = mass / volume
The mass of NaCl can be calculated by multiplying the molar mass of NaCl (58.44 g/mol) by the number of moles.
The volume of NaCl can be calculated using the formula:
Volume = (unit length)^3
Given that the unit length of NaCl is 0.5627 nm, we need to convert it to cm:
0.5627 nm * (1 cm / 10^7 nm) = 5.627 x 10^-9 cm
Now we can calculate the volume:
Volume = (5.627 x 10^-9 cm)^3 = 1.001 x 10^-25 cm^3
Now we can calculate the mass:
Mass = number of moles * molar mass
Assuming we are dealing with 1 mole of NaCl:
Mass = 1 mol * 58.44 g/mol = 58.44 g
Finally, we can calculate the density:
Density = mass / volume = 58.44 g / 1.001 x 10^-25 cm^3
Since the density is given in g/cm^3, we need to convert the volume to cm^3:
1.001 x 10^-25 cm^3 * (10^3 cm^3 / 1 mL) * (1 mL / 1 cm^3) = 1.001 x 10^-22 g/cm^3
Density = 58.44 g / 1.001 x 10^-22 g/cm^3 = 5.830 x 10^21 g/cm^3
Therefore, the density of NaCl is approximately 5.830 x 10^21 g/cm^3.
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By X-ray diffraction methods, the unit length of NaCl is observed to be 0.5627 nm. The density of NaCl is found to be 2.164 g cm–3. The percentage of Na+ and Cl– ions missing is ____________%: (rounded up to 2 decimal place)Correct answer is between '0.72,0.78'. Can you explain this answer?
Question Description
By X-ray diffraction methods, the unit length of NaCl is observed to be 0.5627 nm. The density of NaCl is found to be 2.164 g cm–3. The percentage of Na+ and Cl– ions missing is ____________%: (rounded up to 2 decimal place)Correct answer is between '0.72,0.78'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about By X-ray diffraction methods, the unit length of NaCl is observed to be 0.5627 nm. The density of NaCl is found to be 2.164 g cm–3. The percentage of Na+ and Cl– ions missing is ____________%: (rounded up to 2 decimal place)Correct answer is between '0.72,0.78'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for By X-ray diffraction methods, the unit length of NaCl is observed to be 0.5627 nm. The density of NaCl is found to be 2.164 g cm–3. The percentage of Na+ and Cl– ions missing is ____________%: (rounded up to 2 decimal place)Correct answer is between '0.72,0.78'. Can you explain this answer?.
By X-ray diffraction methods, the unit length of NaCl is observed to be 0.5627 nm. The density of NaCl is found to be 2.164 g cm–3. The percentage of Na+ and Cl– ions missing is ____________%: (rounded up to 2 decimal place)Correct answer is between '0.72,0.78'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about By X-ray diffraction methods, the unit length of NaCl is observed to be 0.5627 nm. The density of NaCl is found to be 2.164 g cm–3. The percentage of Na+ and Cl– ions missing is ____________%: (rounded up to 2 decimal place)Correct answer is between '0.72,0.78'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for By X-ray diffraction methods, the unit length of NaCl is observed to be 0.5627 nm. The density of NaCl is found to be 2.164 g cm–3. The percentage of Na+ and Cl– ions missing is ____________%: (rounded up to 2 decimal place)Correct answer is between '0.72,0.78'. Can you explain this answer?.
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