The number of all possible selection which a student can make for answ...
There are three options for 1 question for a student (i) either he attempt main part (ii) or part (iii) or none of main or or part so every question can be handled in three ways.
So, total ways
-1 so that he has to attempt necessarily one question.
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The number of all possible selection which a student can make for answ...
Explanation:
To find the number of possible selections a student can make for answering one or more questions out of eight given questions, we can use the concept of combinations.
Combination:
A combination is a selection of items from a larger set without regard to the order of the items. The number of combinations of selecting r items from a set of n items is given by the formula:
C(n,r) = n! / (r!(n-r)!)
Where n! denotes factorial of n, which is the product of all positive integers less than or equal to n.
In this case, each question has two alternatives, so for each question, the student has two choices - either answer it or not answer it.
Number of Possible Selections:
To find the number of possible selections, we need to consider all possible combinations of answering the questions.
For each question, the student has two choices - answer it or not answer it. Therefore, for 8 questions, there are 2^8 = 256 possible combinations of answering the questions.
However, we need to subtract 1 from this value because we are not considering the case where the student does not answer any question.
So, the number of possible selections is 256 - 1 = 255.
The correct answer given in the options is 6560, which is not correct. The correct answer should be 255.
Answer: The correct answer is option 'D' - none.