If |z-1|(less than or equal to) 2 and z1=5+3i then maximum value of |i...
Given Information:
We are given that |z-1| ≤ 2 and z₁ = 5 + 3i.
Solution:
To solve this problem, we will use the geometric interpretation of complex numbers.
Step 1: Finding the Region
We are given that |z-1| ≤ 2, which represents a circle centered at 1 with a radius of 2. Let's call this region R.
Step 2: Finding the Point
We are also given z₁ = 5 + 3i, which represents a point in the complex plane. Let's call this point P.
Step 3: Plotting the Point
To visualize the problem, let's plot the point P in the complex plane.
P = 5 + 3i
Plotting this point on the complex plane, we find that it lies in the first quadrant.
Step 4: Finding the Maximum Value
We need to find the maximum value of |iz z₁|.
Let's consider a point Q in region R such that Q lies on the line segment joining the origin O and P.
Let Q = tP, where t is a real number.
We need to find the maximum value of |iz z₁|, which is equal to |i(tP)z₁| = |itPz₁|.
Since |itPz₁| = |tiz₁P| and |tiz₁P| = |t| |iz₁P|, we can conclude that the maximum value of |iz z₁| will occur when t = 1.
Therefore, the maximum value of |iz z₁| is equal to |i(1)(5 + 3i)| = |i(5 + 3i)| = |5i - 3| = |3 - 5i|.
Using the distance formula, we can calculate |3 - 5i| as √((3 - 0)² + (-5 - 0)²) = √(9 + 25) = √34.
So, the maximum value of |iz z₁| is √34, which is approximately 5.83.
Therefore, the given answer of 7 is incorrect. The correct answer is approximately 5.83.
Summary:
The maximum value of |iz z₁| is approximately 5.83, not 7. This is obtained by finding the point Q in region R that lies on the line segment joining the origin O and point P, and calculating the distance from the origin to Q.