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Rahul has two square sheets of side 16 cm each. He cuts the maximum possible number of circles of diameter 4 cm from the first sheet, and the maximum possible number of circles of diameter 1 cm from the second sheet. The total area covered by the circular sheets cut in the 2nd case as compared to the 1st case will:
- a)Increase
- b)Decrease
- c)Remain the same
- d)None of these
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Rahul has two square sheets of side 16 cm each. He cuts the maximum po...
Consider the following cases.
Case 1:
Diameter of each circle = 4 cm
From a square sheet of side 16 cm, maximum 16 circles of diameter 4 cm can be obtained.
Radius of each circle = 2 cm
Total area covered by all 16 circles = 16 * π (22) = 64 πsq. cm
Case 2:
Diameter of each circle = 1 cm
From a square sheet of side 16 cm, maximum 256 circles of diameter 1 cm can be obtained.
Radius of each circle = 0.5 cm
Total area covered by all 256 circles = 256 * π(0.52) = 64 πsq. cm
It can be seen that the area covered in both the cases is the same.
Hence, option 3.
Case 1:
Diameter of each circle = 4 cm
From a square sheet of side 16 cm, maximum 16 circles of diameter 4 cm can be obtained.
Radius of each circle = 2 cm
Total area covered by all 16 circles = 16 * π (22) = 64 πsq. cm
Case 2:
Diameter of each circle = 1 cm
From a square sheet of side 16 cm, maximum 256 circles of diameter 1 cm can be obtained.
Radius of each circle = 0.5 cm
Total area covered by all 256 circles = 256 * π(0.52) = 64 πsq. cm
It can be seen that the area covered in both the cases is the same.
Hence, option 3.
Most Upvoted Answer
Rahul has two square sheets of side 16 cm each. He cuts the maximum po...
Consider the following cases.
Case 1:
Diameter of each circle = 4 cm
From a square sheet of side 16 cm, maximum 16 circles of diameter 4 cm can be obtained.
Radius of each circle = 2 cm
Total area covered by all 16 circles = 16 * π (22) = 64 πsq. cm
Case 2:
Diameter of each circle = 1 cm
From a square sheet of side 16 cm, maximum 256 circles of diameter 1 cm can be obtained.
Radius of each circle = 0.5 cm
Total area covered by all 256 circles = 256 * π(0.52) = 64 πsq. cm
It can be seen that the area covered in both the cases is the same.
Hence, option 3.
Case 1:
Diameter of each circle = 4 cm
From a square sheet of side 16 cm, maximum 16 circles of diameter 4 cm can be obtained.
Radius of each circle = 2 cm
Total area covered by all 16 circles = 16 * π (22) = 64 πsq. cm
Case 2:
Diameter of each circle = 1 cm
From a square sheet of side 16 cm, maximum 256 circles of diameter 1 cm can be obtained.
Radius of each circle = 0.5 cm
Total area covered by all 256 circles = 256 * π(0.52) = 64 πsq. cm
It can be seen that the area covered in both the cases is the same.
Hence, option 3.
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Community Answer
Rahul has two square sheets of side 16 cm each. He cuts the maximum po...
256*pi*1²/(16*pi*4²)=1
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Rahul has two square sheets of side 16 cm each. He cuts the maximum possible number of circles of diameter 4 cm from the first sheet, and the maximum possible number ofcircles of diameter 1 cm from the second sheet. The total area covered by the circular sheets cut in the 2nd case as compared to the 1st case will:a)Increaseb)Decreasec)Remain the samed)None of theseCorrect answer is option 'C'. Can you explain this answer?
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