Two cards are drawn at random from a pack of playing cards. Find the p...
The total number of cards in a pack of playing cards is 52.
There are 4 suits in a deck of cards: hearts, diamonds, clubs, and spades. Each suit contains 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, and King.
To find the probability that one card is a heart and the other is an ace, we need to consider two cases:
Case 1: The first card drawn is a heart and the second card drawn is an ace.
- There are 13 hearts in the deck, so the probability of drawing a heart as the first card is 13/52.
- After the first card is drawn, there are 3 aces left in the deck (Ace of hearts, Ace of diamonds, Ace of clubs), so the probability of drawing an ace as the second card is 3/51 (since there are now only 51 cards left in the deck).
- Therefore, the probability of this case is (13/52) * (3/51) = 1/68.
Case 2: The first card drawn is an ace and the second card drawn is a heart.
- There are 4 aces in the deck, so the probability of drawing an ace as the first card is 4/52.
- After the first card is drawn, there are 12 hearts left in the deck, so the probability of drawing a heart as the second card is 12/51.
- Therefore, the probability of this case is (4/52) * (12/51) = 1/221.
To find the total probability, we need to add the probabilities of both cases together:
1/68 + 1/221 = 289/15228 = 1/52.
Therefore, the probability that one card is a heart and the other is an ace is 1/52.
The correct answer is option 'B' - 1/26.