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In a mid term examination, there are 7 subjects. The maximum marks and passing marks for each subject are 100 and 35 respectively. Ravi scored 40% marks in all and the average of his marks in Mathematics, English and Physics is 48, with the highest marks among these three subjects being 64. If M and m are respectively the maximum and minimum number of subjects in which Ravi could have failed, what is (M - m)?
  • a)
    0
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In a mid term examination, there are 7 subjects. The maximum marks and...
Ravi's total marks = 40% of 700 = 280
Total score in 3 subjects = 48 x 3 = 144
Since the maximum marks in one of the three given subjects is 64, total marks in the remaining two subjects of this group = 144 - 64 = 80
and, total score in remaining 4 subjects = 136
To find M .
80 can be split as 34 + 46
He can fail in at most one of the three given subjects.
For the remaining 4 subjects, 136 can be split as 34 x 4 i.e. he fails in all four subjects. 
M = 4 + 1 = 5
To find m. 80 can be split as 40 + 40.
He doesn't fail in at any of the three given subjects.
For the remaining 4 subjects, 136 can be split as (35 * 3) + 31 i.e. he fails in at most one subject.
m = 1
M-m = 5 - 1 = 4
Hence, option 4.
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Most Upvoted Answer
In a mid term examination, there are 7 subjects. The maximum marks and...
Given information:
- 7 subjects
- Maximum marks and passing marks for each subject are 100 and 35 respectively
- Ravi scored 40% marks in all subjects
- Average of his marks in Mathematics, English and Physics is 48
- Highest marks among these three subjects is 64
- M and m are respectively the maximum and minimum number of subjects in which Ravi could have failed
- Need to find (M-m)

Approach:
- Find Ravi's total marks and compare with passing marks to find number of subjects he failed
- Use the given information about the average marks and highest marks to find which subjects Ravi could have failed
- Calculate M and m based on the above analysis
- Find (M-m)

Detailed solution:
- Ravi scored 40% marks in all subjects, which means he scored (40/100)*7*100 = 280 marks out of 700
- To pass, he needs to score at least 35*7 = 245 marks out of 700
- Therefore, he failed in (700-280)/100 = 4.2 ≈ 4 subjects
- Now, we need to find which subjects he could have failed based on the given information
- Let's assume he scored the highest marks in Mathematics, English and Physics and see if it is possible for him to score an average of 48 in these subjects
- If he scored 64 in each of these subjects and 35 in the remaining 4 subjects, then his total marks would be (64*3 + 35*4) = 271, which is more than the passing marks of 245
- Therefore, it is possible for him to score an average of 48 in Mathematics, English and Physics
- This means he did not fail in any of these subjects
- However, he could have failed in any of the remaining 4 subjects, so m = 0 and M = 4
- Therefore, (M-m) = 4-0 = 4

Answer: Option (d) 4
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In a mid term examination, there are 7 subjects. The maximum marks and passing marks for each subject are 100 and 35 respectively. Ravi scored 40% marks in all and theaverage of his marks in Mathematics, English and Physics is 48, with the highest marks among these three subjects being 64. If M and m are respectively the maximum and minimum number of subjects in which Ravi could have failed, what is (M - m)?a)0b)2c)3d)4Correct answer is option 'D'. Can you explain this answer?
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