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A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.
- a)500°C
- b)900°C
- c)953.6∘C
- d)706.80 °C
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A piece of iron of mass 100g is kept inside a furnace for a long time ...
Mass of Iron = 100g
Water Eq of caloriemeter = 10g
Mass of water = 240g
Let the Temp. of surface = 0ºC
Siron = 470J/kg°C
Water Eq of caloriemeter = 10g
Mass of water = 240g
Let the Temp. of surface = 0ºC
Siron = 470J/kg°C
Total heat gained = Total heat lost.
So,100/1000× 470 × (θ – 60) = 250/1000 × 4200 × (60 – 20)
⇒ 47θ – 47 × 60 = 25 × 42 × 40
⇒ θ = 4200 + 2820/47= 44820/47 =953.61°C
⇒ 47θ – 47 × 60 = 25 × 42 × 40
⇒ θ = 4200 + 2820/47= 44820/47 =953.61°C
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A piece of iron of mass 100g is kept inside a furnace for a long time ...
Mass of iron = 100 g
Water equivalent of calorimeter = 10 g
Mass of water = 240 g
Let the temperature of the surface be ToC
Specific heat of iron = S = 470Jkg−1C−1
Total heat gained = Total heat lost
1000100×470×(T−60)=1000250(4200)(60−20)
T=953.610C
Yoyo
Water equivalent of calorimeter = 10 g
Mass of water = 240 g
Let the temperature of the surface be ToC
Specific heat of iron = S = 470Jkg−1C−1
Total heat gained = Total heat lost
1000100×470×(T−60)=1000250(4200)(60−20)
T=953.610C
Yoyo
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A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer?.
A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer?.
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A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A piece of iron of mass 100g is kept inside a furnace for a long time and Jthen put in a calorimeter of water equivalent 10g containing 240g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470J/kg-°C.a)500°Cb)900°Cc)953.6Cd)706.80 °CCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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