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The coefficient of concurrent.deviationfor p pairs of observations was found to be 1/root3 if the number of concurrent deviations was found to be 6 then the valire of p is ?
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The coefficient of concurrent.deviationfor p pairs of observations was...
Calculation of p in Coefficient of Concurrent Deviation


Given Data:

Coefficient of concurrent deviation = 1/√3

Number of concurrent deviations = 6


Formula:

Coefficient of concurrent deviation = 1/√3 = √(6/(p(p-1)))


Solution:


Substituting the given values in the formula:

1/√3 = √(6/(p(p-1)))


Squaring both sides:

1/3 = 6/(p(p-1))

p(p-1) = 18

p² - p - 18 = 0


Solving the quadratic equation:

p = (1 ± √(1 + 4*18))/2

p = (1 ± √(73))/2

Since, p cannot be negative, p = (1 + √(73))/2


Answer:

The value of p is (1 + √(73))/2
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The coefficient of concurrent.deviationfor p pairs of observations was found to be 1/root3 if the number of concurrent deviations was found to be 6 then the valire of p is ?
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The coefficient of concurrent.deviationfor p pairs of observations was found to be 1/root3 if the number of concurrent deviations was found to be 6 then the valire of p is ? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The coefficient of concurrent.deviationfor p pairs of observations was found to be 1/root3 if the number of concurrent deviations was found to be 6 then the valire of p is ? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coefficient of concurrent.deviationfor p pairs of observations was found to be 1/root3 if the number of concurrent deviations was found to be 6 then the valire of p is ?.
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