Question Description
A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer?.

Solutions for A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer?, a detailed solution for A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer? has been provided alongside types of A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m = 0.4kg is at rest on this surface. An impulse of 1.0Ns is applied to the block at time to t = 0 so that it starts moving along the x-axis with a velocity v(t) = v0e–t/τ, where v0 is a constant and τ= 4s. The displacement of the block, in metres, at t = τ is_____________.Take e−1 = 0.37.Correct answer is '6.30'. Can you explain this answer? tests, examples and also practice JEE tests.