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Let  and M.D. be the mean and the mean deviation about  of n observation xi, i = 1, 2, ...., n. If each of the observation is increased by 5, then the new mean and the mean deviation about the new mean respectively, are:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Letand M.D. be the mean and the mean deviation aboutof n observation x...
The expression for the mean of the n observation is,

The new mean after the increment 5 in each observation is given as,


The expression for the mean deviation of the n observation is,

The new mean deviation after the increment 5 in each observation is given as,
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Letand M.D. be the mean and the mean deviation aboutof n observation xi, i = 1, 2, ...., n. If each of the observation is increased by 5, then the new mean and the mean deviation about the new mean respectively, are:a)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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Letand M.D. be the mean and the mean deviation aboutof n observation xi, i = 1, 2, ...., n. If each of the observation is increased by 5, then the new mean and the mean deviation about the new mean respectively, are:a)b)c)d)Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Letand M.D. be the mean and the mean deviation aboutof n observation xi, i = 1, 2, ...., n. If each of the observation is increased by 5, then the new mean and the mean deviation about the new mean respectively, are:a)b)c)d)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Letand M.D. be the mean and the mean deviation aboutof n observation xi, i = 1, 2, ...., n. If each of the observation is increased by 5, then the new mean and the mean deviation about the new mean respectively, are:a)b)c)d)Correct answer is option 'B'. Can you explain this answer?.
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