Two concentric uniformly charged spheres of radius 10 CM and 20cm pote...
Calculation of Potential Difference between Two Concentric Uniformly Charged Spheres
Given Information
- Radius of the inner sphere = 10 cm
- Radius of the outer sphere = 20 cm
Assumptions
- The charge on both spheres is uniformly distributed.
- The charge on both spheres is spherically symmetric.
Calculation of Potential Difference
The potential difference between two concentric uniformly charged spheres can be calculated using the following formula:
V = k( Q1 / r1 - Q2 / r2 )
Where,
- V = Potential difference between the two spheres
- k = Coulomb's constant = 9 x 10^9 Nm^2/C^2
- Q1 = Charge on the inner sphere
- r1 = Radius of the inner sphere
- Q2 = Charge on the outer sphere
- r2 = Radius of the outer sphere
Since the spheres are uniformly charged, we can calculate the charge on each sphere as:
Q = 4πεr^2σ
Where,
- Q = Charge on the sphere
- ε = Permittivity of free space = 8.85 x 10^-12 C^2/Nm^2
- r = Radius of the sphere
- σ = Surface charge density
Since the charge is uniformly distributed, we can calculate the surface charge density as:
σ = Q / (4πr^2)
Using the above formulas, we can calculate the charge on each sphere:
- Charge on the inner sphere (Q1) = 4πεr1^2σ
- Charge on the outer sphere (Q2) = 4πεr2^2σ
Substituting the above values in the formula for potential difference, we get:
V = k( Q1 / r1 - Q2 / r2 )
V = 9 x 10^9 ( (4πεr1^2σ) / r1 - (4πεr2^2σ) / r2 )
V = 9 x 10^9 ( 4πεσ / r1 - 4πεσ / r2 ) (r1^2r2^2 / r1r2)
V = 36πεσ (r2^2 - r1^2) / r1r2
Substituting the values of ε, σ, r1, and r2, we get:
V = 36π(8.85 x 10^-12)( (1 / 0.1) - (1 / 0.2) ) / 0.1 x 0.2
V =