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A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge –3Q, the new potential difference between the same two surface is xV, then x is :-
    Correct answer is '1'. Can you explain this answer?
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    When the uncharged concentric conducting hollow spherical shell is brought in contact with the solid conducting sphere, the charge on the solid sphere will redistribute itself in such a way that the potential on the surface of the solid sphere becomes equal to that of the outer surface of the hollow shell. This is because the charges on the solid sphere will move to the inner surface of the hollow shell until the potential on the surface of the solid sphere becomes equal to that of the outer surface of the hollow shell.

    Let the charge on the hollow shell after contact be Q'. Then, the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell will be given by:

    V' = Q'/(4πε0R) - Q/(4πε0R)

    where R is the radius of the solid sphere and ε0 is the permittivity of free space.

    The charge on the hollow shell after contact can be found using the principle of conservation of charge:

    Q + 0 = Q' + Q'

    Q' = Q/2

    Substituting this value in the expression for V', we get:

    V' = Q/(8πε0R)

    Therefore, the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell after the shell is given a charge Q'' is given by:

    V'' = (Q + Q'')/(4πε0R) - Q''/(4πε0R)

    = (Q + Q'')/(4πε0R) - Q/(4πε0R) + Q''/(4πε0R)

    = V + Q''/(4πε0R)

    Hence, the potential difference increases by Q''/(4πε0R) when the shell is given a charge Q''.
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    A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge –3Q, the new potential difference between the same two surface is xV, then x is :-Correct answer is '1'. Can you explain this answer?
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    A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge –3Q, the new potential difference between the same two surface is xV, then x is :-Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge –3Q, the new potential difference between the same two surface is xV, then x is :-Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge –3Q, the new potential difference between the same two surface is xV, then x is :-Correct answer is '1'. Can you explain this answer?.
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