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78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3 of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein is
- a)36,500 g mol-1
- b)34,500 g mol-1
- c)35,400 g mol-1
- d)35,600 g mol-1
Correct answer is option 'D'. Can you explain this answer?
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78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl...
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78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl...
°C to form the corresponding diazonium salt (B). The diazonium salt is then treated with CuCN to form the corresponding cyanide derivative (C). The cyanide derivative is hydrolyzed with HCl to give the corresponding carboxylic acid (D). The carboxylic acid has a molar mass of 176 g/mol and contains an aliphatic side chain. Determine the identity of the amino acid (A).
To determine the identity of the amino acid (A), we need to consider the reactions involved and the molar masses of the compounds.
1. Formation of diazonium salt (B):
The conversion of an amino acid to a diazonium salt involves the reaction with NaNO2/HCl. This reaction replaces the amino group (-NH2) of the amino acid with a diazonium group (-N2+). The molar mass of the diazonium salt is equal to the molar mass of the amino acid minus one nitrogen atom (N2).
2. Formation of cyanide derivative (C):
The diazonium salt (B) reacts with CuCN to form the cyanide derivative (C). This reaction replaces the diazonium group (-N2+) with a cyanide group (-CN). The molar mass of the cyanide derivative is equal to the molar mass of the diazonium salt minus one nitrogen atom (N2).
3. Hydrolysis of cyanide derivative to carboxylic acid (D):
The cyanide derivative (C) is hydrolyzed with HCl to give the carboxylic acid (D). This reaction replaces the cyanide group (-CN) with a carboxylic acid group (-COOH). The molar mass of the carboxylic acid is equal to the molar mass of the cyanide derivative plus one oxygen atom (O).
Given that the molar mass of the carboxylic acid (D) is 176 g/mol and it contains an aliphatic side chain, we can deduce the following:
Molar mass of amino acid (A) = Molar mass of carboxylic acid (D) + Molar mass of one nitrogen atom (N) - Molar mass of one oxygen atom (O)
Molar mass of amino acid (A) = 176 g/mol + 14 g/mol - 16 g/mol = 174 g/mol
Now, we need to consider the possible amino acids with a molar mass of 174 g/mol. Some options include:
- Methionine (C5H11NO2S)
- Leucine (C6H13NO2)
- Isoleucine (C6H13NO2)
- Valine (C5H11NO2)
Among these options, the only amino acid that is optically active (contains an asymmetric carbon) is Isoleucine (C6H13NO2). Therefore, the identity of the amino acid (A) is Isoleucine.
To determine the identity of the amino acid (A), we need to consider the reactions involved and the molar masses of the compounds.
1. Formation of diazonium salt (B):
The conversion of an amino acid to a diazonium salt involves the reaction with NaNO2/HCl. This reaction replaces the amino group (-NH2) of the amino acid with a diazonium group (-N2+). The molar mass of the diazonium salt is equal to the molar mass of the amino acid minus one nitrogen atom (N2).
2. Formation of cyanide derivative (C):
The diazonium salt (B) reacts with CuCN to form the cyanide derivative (C). This reaction replaces the diazonium group (-N2+) with a cyanide group (-CN). The molar mass of the cyanide derivative is equal to the molar mass of the diazonium salt minus one nitrogen atom (N2).
3. Hydrolysis of cyanide derivative to carboxylic acid (D):
The cyanide derivative (C) is hydrolyzed with HCl to give the carboxylic acid (D). This reaction replaces the cyanide group (-CN) with a carboxylic acid group (-COOH). The molar mass of the carboxylic acid is equal to the molar mass of the cyanide derivative plus one oxygen atom (O).
Given that the molar mass of the carboxylic acid (D) is 176 g/mol and it contains an aliphatic side chain, we can deduce the following:
Molar mass of amino acid (A) = Molar mass of carboxylic acid (D) + Molar mass of one nitrogen atom (N) - Molar mass of one oxygen atom (O)
Molar mass of amino acid (A) = 176 g/mol + 14 g/mol - 16 g/mol = 174 g/mol
Now, we need to consider the possible amino acids with a molar mass of 174 g/mol. Some options include:
- Methionine (C5H11NO2S)
- Leucine (C6H13NO2)
- Isoleucine (C6H13NO2)
- Valine (C5H11NO2)
Among these options, the only amino acid that is optically active (contains an asymmetric carbon) is Isoleucine (C6H13NO2). Therefore, the identity of the amino acid (A) is Isoleucine.
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78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl...
35,600 g mol
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78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer?
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78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about 78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer?.
78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about 78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer?.
Solutions for 78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 9.
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78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer?, a detailed solution for 78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of 78 g of an optically active L-amino acid (A) is treated with NaNO2/HCl at 0º C. 448 cm3of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein isa)36,500 g mol-1b)34,500 g mol-1c)35,400 g mol-1d)35,600 g mol-1Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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