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A milkman uses 3 containers of the same size to store milk.
Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk from container 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:
Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk from container 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:
- a)22%
- b)26%
- c)24%
- d)Either 2 or 3
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A milkman uses 3 containers of the same size to store milk.Initially, ...
Without loss of generality, we can assume that the volume (or capacity) of each container is 1 unit.
Let x units be the volume of milk poured from container 1 to container 3.
Since the volume of container 3 is 1 unit, (1 - x) units is the volume of milk poured from container 2 to container 3.
The concentration of water in containers 1 and 2 is 20% and 30% respectively.
Hence, the volume of water in container 3 = (0.2 x x) + [0.3 x (1 - x)] = 0.3 - 0.1x
As the volume of container 3 is 1 unit, the concentration of water in container 3 is nothing but the volume of water in that container.
Hence, the concentration of water in container 3 is (0.3 - 0.1x)%.
Now, the volume of water remaining in container 1 is (1 - x) x 0.2 units and the volume of liquid remaining in container 1 is (1 - x) units
Now, milk is poured back from container 3 to containers 1 and 2 such that both are completely filled.
The above two statements imply that x units (volume) of milk is poured back from container 3 to container 1.
Hence, volume of water in container 1 is,
(1 - x) x 0.2 + (0 .3 -0 .1x) x x = 0 .1 x - 0 .1 x 2 + 0.2
But the concentration of water in container 1 after pouring milk from container 3 is 0.216 i.e. 21.6%.
0.1x-0.1x2 + 0.2 = 0.216
0.1x2 - 0.1x + 0.016 = 0
x2 - x + 0.16 = 0
Solving the above equation, we get, x = 0.8 orx = 0.2
Hence, concentration of water in container 3 is,
0.3 - (0.1 x 0.8) = 0.22 (22%), or
0.3-(0.1 x 0.2) = 0.28 (28%)
Here, only 22% is given as an answer option.
Hence, option 1.
Let x units be the volume of milk poured from container 1 to container 3.
Since the volume of container 3 is 1 unit, (1 - x) units is the volume of milk poured from container 2 to container 3.
The concentration of water in containers 1 and 2 is 20% and 30% respectively.
Hence, the volume of water in container 3 = (0.2 x x) + [0.3 x (1 - x)] = 0.3 - 0.1x
As the volume of container 3 is 1 unit, the concentration of water in container 3 is nothing but the volume of water in that container.
Hence, the concentration of water in container 3 is (0.3 - 0.1x)%.
Now, the volume of water remaining in container 1 is (1 - x) x 0.2 units and the volume of liquid remaining in container 1 is (1 - x) units
Now, milk is poured back from container 3 to containers 1 and 2 such that both are completely filled.
The above two statements imply that x units (volume) of milk is poured back from container 3 to container 1.
Hence, volume of water in container 1 is,
(1 - x) x 0.2 + (0 .3 -0 .1x) x x = 0 .1 x - 0 .1 x 2 + 0.2
But the concentration of water in container 1 after pouring milk from container 3 is 0.216 i.e. 21.6%.
0.1x-0.1x2 + 0.2 = 0.216
0.1x2 - 0.1x + 0.016 = 0
x2 - x + 0.16 = 0
Solving the above equation, we get, x = 0.8 orx = 0.2
Hence, concentration of water in container 3 is,
0.3 - (0.1 x 0.8) = 0.22 (22%), or
0.3-(0.1 x 0.2) = 0.28 (28%)
Here, only 22% is given as an answer option.
Hence, option 1.
Most Upvoted Answer
A milkman uses 3 containers of the same size to store milk.Initially, ...
Given Information:
- Container 1 and container 2 are initially filled with diluted milk.
- The water concentration in container 1 is 20%.
- The water concentration in container 2 is 30%.
- Container 3 is initially empty.
Process:
1. The milk from container 1 and container 2 is poured into container 3, filling it completely.
2. The milk from container 3 is poured back into containers 1 and 2, filling them completely.
Let's assume:
- The initial volume of milk in containers 1 and 2 = M liters each.
- The volume of milk poured into container 3 = X liters.
- The concentration of water in container 3 after mixing = C%.
Calculations:
1. Initially, the volume of water in container 1 = 0.2M liters (20% of M liters).
2. Initially, the volume of water in container 2 = 0.3M liters (30% of M liters).
3. After pouring the milk from containers 1 and 2 into container 3, the total volume of milk in container 3 = 2M liters.
4. The volume of water in container 3 after mixing = 0.2M + 0.3M = 0.5M liters.
5. The concentration of water in container 3 after mixing = (Volume of water in container 3 / Total volume of milk in container 3) * 100
= (0.5M / 2M) * 100
= 25%.
Conclusion:
The concentration of water in container 3 after mixing is 25%. Therefore, the concentration of water in container 3 could have been 25%.
- Container 1 and container 2 are initially filled with diluted milk.
- The water concentration in container 1 is 20%.
- The water concentration in container 2 is 30%.
- Container 3 is initially empty.
Process:
1. The milk from container 1 and container 2 is poured into container 3, filling it completely.
2. The milk from container 3 is poured back into containers 1 and 2, filling them completely.
Let's assume:
- The initial volume of milk in containers 1 and 2 = M liters each.
- The volume of milk poured into container 3 = X liters.
- The concentration of water in container 3 after mixing = C%.
Calculations:
1. Initially, the volume of water in container 1 = 0.2M liters (20% of M liters).
2. Initially, the volume of water in container 2 = 0.3M liters (30% of M liters).
3. After pouring the milk from containers 1 and 2 into container 3, the total volume of milk in container 3 = 2M liters.
4. The volume of water in container 3 after mixing = 0.2M + 0.3M = 0.5M liters.
5. The concentration of water in container 3 after mixing = (Volume of water in container 3 / Total volume of milk in container 3) * 100
= (0.5M / 2M) * 100
= 25%.
Conclusion:
The concentration of water in container 3 after mixing is 25%. Therefore, the concentration of water in container 3 could have been 25%.
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A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer?
Question Description
A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer?.
A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer?.
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A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A milkman uses 3 containers of the same size to store milk.Initially, container 1 and container 2 are completely filled with diluted milk and container 3 is empty. The water concentration in containers 1 and 2 is 20% and 30% respectively. Some milk from container 1 and some milk from container 2 is poured into container 3, such that container 3 gets completely filled. Now, milk fromcontainer 3 is poured back into containers 1 and 2, such that both are completely filled. If the water concentration in container 1 is now 21.6%, then the concentration of water in container 3 could have been:a)22%b)26%c)24%d)Either 2 or 3Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice CAT tests.
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