The value AH of the reaction.CH2Cl2(g) → C(g)+2H(g) + 2Cl(g)The a...
Understanding the Reaction
The given reaction is:
CH2Cl2(g) → C(g) + 2H(g) + 2Cl(g)
To find the enthalpy change (ΔH) of the reaction, we need to consider the bond energies involved.
Bond Energies
- Average bond energy of C-H: 416 kJ/mol
- Average bond energy of C-Cl: 328 kJ/mol
Breaking Bonds
In CH2Cl2, the bonds that need to be broken are:
- 2 C-H bonds
- 2 C-Cl bonds
The total energy required to break these bonds is calculated as follows:
- Energy to break 2 C-H bonds: 2 × 416 kJ/mol = 832 kJ
- Energy to break 2 C-Cl bonds: 2 × 328 kJ/mol = 656 kJ
Total Energy Required
- Total energy required to break all bonds in CH2Cl2:
832 kJ + 656 kJ = 1488 kJ
Forming Atoms
When forming the products (C, H, and Cl), no bonds are formed as they are in their atomic states. Therefore, no energy is released during this step.
Calculating ΔH
The overall reaction enthalpy change (ΔH) is:
ΔH = Energy required to break bonds - Energy released by forming products
Since no energy is released in forming atoms:
ΔH = 1488 kJ - 0 kJ = 1488 kJ
Conclusion
Thus, the enthalpy change (ΔH) for the reaction is 1488 kJ, confirming that the correct answer is option 'C'.