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In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :
  • a)
    AB2
  • b)
    A5B2
  • c)
    A2B3
  • d)
    A2B5
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In a face centered cubic lattice atoms A are at the corner points and ...

Effective number of atoms at corner = 8 x 1/8
Effective number of atoms at tha face = 
= 5/2
The ratio of effective number of atoms

Therefore, the formula of the compound is A2B5 
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Community Answer
In a face centered cubic lattice atoms A are at the corner points and ...
A=8×1/8=1
B=1/2×5=5/2
A1×B5/2=A2×B5
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In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :a)AB2b)A5B2c)A2B3d)A2B5Correct answer is option 'D'. Can you explain this answer?
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In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :a)AB2b)A5B2c)A2B3d)A2B5Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :a)AB2b)A5B2c)A2B3d)A2B5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :a)AB2b)A5B2c)A2B3d)A2B5Correct answer is option 'D'. Can you explain this answer?.
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