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find x if 4^2x-1 - 16x
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Most Upvoted Answer
find x if 4^2x-1 - 16x Related: Plz find attachment?
Finding x in 4^2x-1 - 16x

Given: 4^2x-1 - 16x

To find: value of x

Solution:

Step 1: Simplify the given expression

4^2x-1 - 16x can be written as (2^2)2x-1 - 2^4x

Using exponential laws, we can simplify it as 2^4x-2 - 2^4x

This further simplifies to 2^4x-2(1-2)

= 2^4x-2 * (-1) = -2^-(2x+2)

Step 2: Equate the expression obtained in Step 1 to zero

-2^-(2x+2) = 0

This is only possible if the exponent is negative infinity, which means 2x+2 = -∞

Step 3: Solve for x

2x+2 = -∞

2x = -∞ - 2

2x = -∞ (as -∞ - 2 = -∞)

x = (-∞)/2 = -∞

Therefore, the value of x is -∞.

Conclusion:

The value of x in 4^2x-1 - 16x is -∞.
Community Answer
find x if 4^2x-1 - 16x Related: Plz find attachment?
Well I think something is missing in the question.
may be this is the question: 4^(2x-1) - 16^(x-1)=384
solution:
4^(2x-1)-16^(x-1)=384
》 (2²)^(2x-1)-(2⁴)^(x-1)=384
》(2)^(4x-2)-(2)^(4x-4)=384
》2^(4x)[ 2^(-2)-2^(-4)] =384
》2^(4x) [ 1/4-1/16] =384
》2^(4x)[3/16] =384
》2^(4x)=128×16
》2^(4x)=2⁷×2⁴
》2^(4x)=2^(11)
》4x=11
》x=11/4

hope it helps.
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