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In forced circulation boilers, about 90% of water is recirculated without evaporation. The circulation ratio is
- a)0.1
- b)0.9
- c)9
- d)10
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In forced circulation boilers, about 90% of water is recirculated with...
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A forced circulation boiler is a boiler where a pump is used to circulate water inside the boiler. This differs from a natural circulation boiler which relies on current density to circulate water inside the boiler. In some forced circulation boilers, the water is circulated twenty times the rate of evaporation.
-In forced circulation boilers, about 90% of water is recirculated without evaporation. The circulation ratio is 10.
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In forced circulation boilers, about 90% of water is recirculated with...
In forced circulation boilers, the circulation ratio is the ratio of the mass of water recirculated to the mass of water evaporated. In this case, it is stated that about 90% of the water is recirculated without evaporation.
To determine the circulation ratio, we need to calculate the mass of water recirculated and the mass of water evaporated. Let's assume that the total mass of water flowing through the boiler is M.
The mass of water recirculated can be calculated by multiplying the total mass of water by the fraction that is recirculated without evaporation, which is 90% or 0.9. Therefore, the mass of water recirculated is 0.9M.
The mass of water evaporated can be calculated by subtracting the mass of water recirculated from the total mass of water. Therefore, the mass of water evaporated is M - 0.9M = 0.1M.
The circulation ratio is then calculated by dividing the mass of water recirculated by the mass of water evaporated:
Circulation ratio = (mass of water recirculated) / (mass of water evaporated)
= (0.9M) / (0.1M)
= 9
Therefore, the circulation ratio in this case is 9. This means that for every 1 unit of water evaporated, 9 units of water are recirculated without evaporation.
Hence, the correct answer is option 'D' (10), which is the value of the circulation ratio calculated in this case.
To determine the circulation ratio, we need to calculate the mass of water recirculated and the mass of water evaporated. Let's assume that the total mass of water flowing through the boiler is M.
The mass of water recirculated can be calculated by multiplying the total mass of water by the fraction that is recirculated without evaporation, which is 90% or 0.9. Therefore, the mass of water recirculated is 0.9M.
The mass of water evaporated can be calculated by subtracting the mass of water recirculated from the total mass of water. Therefore, the mass of water evaporated is M - 0.9M = 0.1M.
The circulation ratio is then calculated by dividing the mass of water recirculated by the mass of water evaporated:
Circulation ratio = (mass of water recirculated) / (mass of water evaporated)
= (0.9M) / (0.1M)
= 9
Therefore, the circulation ratio in this case is 9. This means that for every 1 unit of water evaporated, 9 units of water are recirculated without evaporation.
Hence, the correct answer is option 'D' (10), which is the value of the circulation ratio calculated in this case.
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In forced circulation boilers, about 90% of water is recirculated without evaporation. The circulation ratio isa)0.1b)0.9c)9d)10Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In forced circulation boilers, about 90% of water is recirculated without evaporation. The circulation ratio isa)0.1b)0.9c)9d)10Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In forced circulation boilers, about 90% of water is recirculated without evaporation. The circulation ratio isa)0.1b)0.9c)9d)10Correct answer is option 'D'. Can you explain this answer?.
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