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The velocity of water in a river is 18 km/hr near the surface. If the river is 5 m deep, find the shearing stress between the horizontal layers of water. The co-efficient of viscosity of water = 10–2 poise.
  • a)
    10–1 N/m2
  • b)
    10–4 N/m2
  • c)
    10–2 N/m2
  • d)
    10–3 N/m2
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The velocity of water in a river is 18 km/hr near the surface. If the ...
F = – nA dv/dx

now stress = F/A = 10–3
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The velocity of water in a river is 18 km/hr near the surface. If the ...
Given data:
- Velocity of water = 18 km/hr
- Depth of river = 5 m
- Co-efficient of viscosity of water = 10^-2 poise

Calculating the shear stress:
1. Convert the velocity of water from km/hr to m/s:
18 km/hr = 18 * 1000 / 3600 m/s = 5 m/s
2. Calculate the shear rate:
Shear rate = Velocity / Depth = 5 / 5 = 1 s^-1
3. Calculate the shear stress using the formula:
Shear stress = Co-efficient of viscosity * Shear rate
= 10^-2 * 1
= 10^-2 N/m^2
= 10^-3 N/m^2
Therefore, the shear stress between the horizontal layers of water in the river is 10^-3 N/m^2, which corresponds to option 'D'.
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The velocity of water in a river is 18 km/hr near the surface. If the river is 5 m deep, find the shearing stress between the horizontal layers of water. The co-efficient of viscosity of water = 10–2 poise.a)10–1 N/m2b)10–4 N/m2c)10–2 N/m2d)10–3 N/m2Correct answer is option 'D'. Can you explain this answer?
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