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A simply supported beam carrying a concentrated load W at mid -span deflects by δ1 under the load. If the same beam carries the load W such that it is distributed uniformly over entire length and undergoes a deflection δ2 at the mid span. The ratio δ1: δ2 is
IES-1995; GATE-1994]
- a)2: 1
- b)√2 : 1
- c)1: 1
- d)8: 5
Correct answer is option 'D'. Can you explain this answer?
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A simply supported beam carrying a concentrated load W at mid -span de...
Therefore δ1: δ2 = 8: 5
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A simply supported beam carrying a concentrated load W at mid -span de...
The deflection of a simply supported beam carrying a concentrated load W at mid-span can be calculated using the formula:
δ = (W * L^3) / (48 * E * I)
Where:
δ = deflection at mid-span
W = concentrated load
L = length of the beam
E = elastic modulus of the material
I = moment of inertia of the beam's cross-sectional area
This formula assumes that the beam is made of a homogeneous material and has a constant cross-sectional area along its length. It also assumes that the beam is in the linear elastic range, meaning that it does not deform plastically.
It's important to note that this formula gives the deflection at mid-span, which is the maximum deflection for a simply supported beam with a concentrated load at mid-span. The deflection will be zero at the supports and will increase linearly towards the mid-span.
If you provide more specific values for the load, beam length, material properties, and moment of inertia, I can calculate the deflection for you.
δ = (W * L^3) / (48 * E * I)
Where:
δ = deflection at mid-span
W = concentrated load
L = length of the beam
E = elastic modulus of the material
I = moment of inertia of the beam's cross-sectional area
This formula assumes that the beam is made of a homogeneous material and has a constant cross-sectional area along its length. It also assumes that the beam is in the linear elastic range, meaning that it does not deform plastically.
It's important to note that this formula gives the deflection at mid-span, which is the maximum deflection for a simply supported beam with a concentrated load at mid-span. The deflection will be zero at the supports and will increase linearly towards the mid-span.
If you provide more specific values for the load, beam length, material properties, and moment of inertia, I can calculate the deflection for you.
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A simply supported beam carrying a concentrated load W at mid -span deflects by δ1 under the load. If the same beam carries the load W such that it is distributed uniformly over entire length and undergoes a deflection δ2 at the mid span. The ratio δ1: δ2 isIES-1995; GATE-1994]a)2: 1b)√2 : 1c)1: 1d)8: 5Correct answer is option 'D'. Can you explain this answer?
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A simply supported beam carrying a concentrated load W at mid -span deflects by δ1 under the load. If the same beam carries the load W such that it is distributed uniformly over entire length and undergoes a deflection δ2 at the mid span. The ratio δ1: δ2 isIES-1995; GATE-1994]a)2: 1b)√2 : 1c)1: 1d)8: 5Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A simply supported beam carrying a concentrated load W at mid -span deflects by δ1 under the load. If the same beam carries the load W such that it is distributed uniformly over entire length and undergoes a deflection δ2 at the mid span. The ratio δ1: δ2 isIES-1995; GATE-1994]a)2: 1b)√2 : 1c)1: 1d)8: 5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simply supported beam carrying a concentrated load W at mid -span deflects by δ1 under the load. If the same beam carries the load W such that it is distributed uniformly over entire length and undergoes a deflection δ2 at the mid span. The ratio δ1: δ2 isIES-1995; GATE-1994]a)2: 1b)√2 : 1c)1: 1d)8: 5Correct answer is option 'D'. Can you explain this answer?.
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