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The magnetic field (in Tesla) required for flipping a 1H nucleus in an NMR spectrometer operating at 400 MHz is _______ [Given: g = 2.67 × 108 T–1 s–1, π = 3.14]
    Correct answer is between '9,10'. Can you explain this answer?
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    The magnetic field (in Tesla) required for flipping a 1H nucleus in an...
    Given:
    - NMR spectrometer operating at 400 MHz
    - g = 2.67 x 10^8 T1 s1
    - θ = 3.14

    To find:
    The magnetic field required for flipping a 1H nucleus in the NMR spectrometer.

    Solution:
    The resonance frequency in Nuclear Magnetic Resonance (NMR) is given by the Larmor equation:

    ω = γB

    Where:
    ω is the resonance frequency
    γ is the gyromagnetic ratio
    B is the magnetic field strength

    In this case, we need to find the magnetic field strength B required for a 1H nucleus with a resonance frequency of 400 MHz.

    Step 1: Convert the resonance frequency from MHz to Hz:
    400 MHz = 400 x 10^6 Hz

    Step 2: Substitute the values into the Larmor equation to find the gyromagnetic ratio γ:
    400 x 10^6 Hz = γB

    Step 3: Rearrange the equation to solve for γ:
    γ = (400 x 10^6 Hz) / B

    Step 4: Substitute the given values for γ and solve for B:
    2.67 x 10^8 T^-1 s^-1 = (400 x 10^6 Hz) / B

    Step 5: Rearrange the equation to solve for B:
    B = (400 x 10^6 Hz) / (2.67 x 10^8 T^-1 s^-1)

    Step 6: Simplify the equation:
    B = 1.498 T

    The magnetic field required for flipping a 1H nucleus in the NMR spectrometer is 1.498 Tesla.

    Conclusion:
    The correct answer is between '1.49' and '1.50'.
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    The magnetic field (in Tesla) required for flipping a 1H nucleus in an NMR spectrometer operating at 400 MHz is _______ [Given: g = 2.67 108 T1 s1, = 3.14]Correct answer is between '9,10'. Can you explain this answer?
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